Consider two almost calibrated Lagrangians $L^{1},L^{2}$ with a unique intersection point $p$, and there is a Darboux chart around $p$ modelled on $B_{1}\subset\mathbb{C}^{n}$, such that inside the chart $L^{1},L^{2}$ the local setup is

$$L^{1}=e^{i\pi/n}\mathbb{R}^{n},\quad L^{2}=\mathbb{R}^{n},\quad\omega=\frac{\sqrt{-1}}{2}\sum dz_{k}\wedge d\bar{z}_{k},\quad\Omega\approx\prod dz_{k}.$$

Let $(L_{t})_{0<t\ll 1}$ be a 1-parameter family of Lagrangian connected sums with neck length $O(t)$, which all agree with $L_{1}\cup L_{2}$ except in a compact subset in $B_{1}$. Inside $B_{1}$, we take the ansatz

$$L_{t}=\{(t\gamma(s)x_{1},\ldots,t\gamma(s)x_{n})|x_{1}^{2}+\ldots x_{n}^{2}=1\},$$

where the curve $\gamma(s):\mathbb{R}\to\mathbb{C}$ can be chosen so that $L_{t}$ is almost calibrated and agrees with $L_{1}\cup L_{2}$ outside $B_{1/2}$. Clearly, $L_{t}$ are related by scaling inside $B_{1}$. The Hamiltonian vector field along $L_{t}$, which is really a section of $(TX/TL_{t})|_{L_{t}}$, agrees with $(\gamma(s)x_{1},\ldots,\gamma(s)x_{n})$ inside $B_{1}$ and is zero outside.³⁸³⁸ 38 This is consistent because near the boundary of $B_{1}$, the position vector is a tangent vector of $L$, so vanishes in the quotient $TX/TL_{t}$. The corresponding Hamiltonian function $h_{t}$ is $t^{2}$ times a smooth function of one variable $s$; a small caveat is that $h_{t}$ converges to two generally different constants along $L_{1}$ and $L_{2}$. Thus it takes finite distance in the Solomon metric to reach the limit $t\to 0$, and the Solomon functional remains finite, but the topology changes from $L_{t}$ to $L^{1}\cup L^{2}$.