ScalingStacks

Proof: [03W6]

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Proof: Using definitions from Section 7.2 one sees immediately that the statement of the Lemma follows from the equality pΩc​a​n​(1+η)=1p_{\Omega^{can}}(1+\eta)=1, which is straightoforward: pΩc​a​n​(1+η)=e​x​p​(R​e​s​(Ωc​a​n​log⁡(1+η)))=1∈𝒪K×p_{\Omega^{can}}(1+\eta)=exp\left(Res(\Omega^{can}\,\log(1+\eta))\right)=1\in{\cal O}_{K}^{\times}. ■\,\blacksquare

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