ScalingStacks

Lemma 5.4 . [053S]

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Lemma 5.4.

As z→∞z\rightarrow\infty we have

(5.43) 𝒢k​(z)\displaystyle\mathcal{G}_{k}(z) ∼12​π⋅(λkn)14⋅e2​λkn⋅zn2zn−24,\displaystyle\sim\frac{1}{2\sqrt{\pi}\cdot(\frac{\lambda_{k}}{n})^{\frac{1}{4}}}\cdot\frac{e^{2\sqrt{\frac{\lambda_{k}}{n}}\cdot z^{\frac{n}{2}}}}{z^{\frac{n-2}{4}}},
(5.44) 𝒟k​(z)\displaystyle\mathcal{D}_{k}(z) ∼π2​(λkn)14⋅e−2λkn⋅zn2zn−24.\displaystyle\sim\frac{\sqrt{\pi}}{2(\frac{\lambda_{k}}{n})^{\frac{1}{4}}}\cdot\frac{e^{-2\sqrt{\frac{\lambda_{k}}{n}}\cdot z^{\frac{n}{2}}}}{z^{\frac{n-2}{4}}}.

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