Lemma 4.10 . [0525] Original official author HTML, exact retained edition. Historical TeX conversion verdicts remain unchanged. Cited-edition alignment and mathematical self-containment are not assessed.
Source coverage notes Source fidelity gap: the original arXiv HTML omits an author TeX footnote attached to equation e:def-omega, including its reference to Remark r:error-function. The retained HTML is preserved as published; the original author TeX remains available. TeX correspondence is not complete. Complete original source context · Original author HTML
Lemma 4.10 .
We have
(4.127) A − − ∫ T − 0 h ( u ) 𝑑 u = 1 2 log ‖ S H ‖ + B T A_{-}-\int_{T_{-}}^{0}h(u)du=\frac{1}{2}\log{\|S_{H}\|}+B_{T}
(4.128) A + + ∫ T + 0 h ( u ) 𝑑 u = 1 2 log ‖ S H ‖ + B T A_{+}+\int_{T_{+}}^{0}h(u)du=\frac{1}{2}\log{\|S_{H}\|}+B_{T}