Lemma 3.14 (Rearrangement Lemma) . [0503] Original official author HTML, exact retained edition. Historical TeX conversion verdicts remain unchanged. Cited-edition alignment and mathematical self-containment are not assessed.
Source coverage notes Source fidelity gap: the original arXiv HTML omits an author TeX footnote attached to equation e:def-omega, including its reference to Remark r:error-function. The retained HTML is preserved as published; the original author TeX remains available. TeX correspondence is not complete. Complete original source context · Original author HTML
Lemma 3.14 (Rearrangement Lemma).
(3.115) A i , α + 1 , β A j , α + 2 , γ y β y γ d y α ∧ d x i ∧ d x j = 1 2 ( A i α , α + 1 A j α , α + 2 − A i α , α + 2 A j α , α + 1 ) y α ⋅ r d r ∧ d x i ∧ d x j . A_{i,\alpha+1,\beta}A_{j,\alpha+2,\gamma}y_{\beta}y_{\gamma}dy_{\alpha}\wedge dx_{i}\wedge dx_{j}=\frac{1}{2}(A_{i\alpha,\alpha+1}A_{j\alpha,\alpha+2}-A_{i\alpha,\alpha+2}A_{j\alpha,\alpha+1})y_{\alpha}\cdot rdr\wedge dx_{i}\wedge dx_{j}.