Proof. [02VE]
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Proof.
Assume that is semipositive. Let be a point of and let be primitive. Since the condition of being concave is closed, if we prove that, for all choices of and , the restriction of to the line is concave, we will deduce that the function is concave. Let such that . Then is a finite extension of and there is a unique extension of the absolute value of to . We will denote with ′ the objects obtained by base change to . Let such that . We consider the affine map given by , and let be the linear part of . We consider the equivariant morphism of Theorem 4.9. The metric induces an algebraic semipositive metric on the restriction of (the line bundle obtained from by base change to ) to . By propositions 5.24 and 5.53(3) we obtain that
By Corollary 5.66 the left-hand side function is concave. Thus the restriction of to is concave. We conclude that is concave. ∎