ScalingStacks

Proof. [02RT]

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Proof.

Symmetry and reflexivity are straightforward. For transitivity assume that we have toric models (𝒳i,Di,ei)({\mathcal{X}}_{i},D_{i},e_{i}), i=1,2,3i=1,2,3, that the first and second model are equivalent through (𝒳′,D′,e′)({\mathcal{X}}^{\prime},D^{\prime},e^{\prime}) and that the second and the third are equivalent through (𝒳′′,D′′,e′′)({\mathcal{X}}^{\prime\prime},D^{\prime\prime},e^{\prime\prime}). Then, by Theorem 4.60, 𝒳′{\mathcal{X}}^{\prime} and 𝒳′′{\mathcal{X}}^{\prime\prime} are defined by SCR polyhedral complexes Π′\Pi^{\prime} and Π′′\Pi^{\prime\prime} respectively, with rec⁡(Π′)=rec⁡(Π′′)=Σ\operatorname{rec}(\Pi^{\prime})=\operatorname{rec}(\Pi^{\prime\prime})=\Sigma. Let Π′′′=Π′⋅Π′′\Pi^{\prime\prime\prime}=\Pi^{\prime}\cdot\Pi^{\prime\prime}. By Lemma 3.11, rec⁡(Π′′′)=Σ\operatorname{rec}(\Pi^{\prime\prime\prime})=\Sigma. Thus Π′′′\Pi^{\prime\prime\prime} determines a model 𝒳′′′{\mathcal{X}}^{\prime\prime\prime} of XΣX_{\Sigma}. This model has morphisms β′\beta^{\prime} and β′′\beta^{\prime\prime} to 𝒳′{\mathcal{X}}^{\prime} and 𝒳′′{\mathcal{X}}^{\prime\prime} respectively. We put e′′′=e′​e′′e^{\prime\prime\prime}=e^{\prime}e^{\prime\prime} and D′′′=e′′β′∗D′=e′β′′∗D′′D^{\prime\prime\prime}=e^{\prime\prime}\beta^{\prime}{}^{\ast}D^{\prime}=e^{\prime}\beta^{\prime\prime}{}^{\ast}D^{\prime\prime}. Now it is easy to verify that (𝒳′′′,D′′′,e′′′)({\mathcal{X}}^{\prime\prime\prime},D^{\prime\prime\prime},e^{\prime\prime\prime}) provides the transitivity property. ∎

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