3.6. Comparison of algebra norms [00N8]
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3.6. Comparison of algebra norms
We compare the quotient algebra norm and the supremum algebra norm on the restricted section algebra, and get directly a (non-uniform) extension theorem.
Proposition 3.24.
Let be an upper-semicontinuous metric on . Then
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Proof.
By definition, for any , one has
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Since the -linear map is surjective for all large , and is the quotient norm of , one has
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Hence the two envelop metrics are equal.
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Lemma 3.25.
Let be an asymptotic Fubini-Study metric on . Then is an asymptotic Fubini-Study metric on .
Proof.
Suppose that is the pointwise limit on of , where are norms on . Then is the pointwise limit of on .
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Proposition 3.26.
Let be a asymptotic Fubini-Study metric on . Consider two algebra norms and on . Then the three metrics are equal
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Proof.
By Proposition 3.24,
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It suffices to show the second equality. By Lemma 3.25, is an asymptotic Fubini-Study metric on . By Proposition 3.12,
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Corollary 3.27.
Let be a asymptotic Fubini-Study metric on . Then on , the spectral algebra seminorm of is equal to . There exists a canonical homeomorphism
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Proof.
By Theorem 2.33, one has a homeomorphism
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by Proposition 3.26, one has
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By Proposition 2.30, the two power-multiplicative algebra seminorms and on are equal since they are both supremum norms on the same spectrum.
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Theorem 3.28.
Let be an asymptotic Fubini-Study metric on , then for any , and any , there exists such that for any , there exists with and
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Proof.
For any , we have . By Corollary 3.27, for any , there exists such that for ,
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It is easy to see that there exists such that the set of integers
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contains a subset of form : the case is clear; if , the fact that and are coprime guarantees the existence of . Note that is power-multiplicative, so for any , there exists with such that
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