ScalingStacks

Verified tagged author-source HTML · 1912.02360v1 · cited publication edition alignment unverified.

00SL

Lemma 5.2. Let uu be a bounded convex function on the square {|xi|<1}⊂ℝn\{|x_{i}|<1\}\subset\mathbb{R}^{n}. Via the rescaled log map s−1​Log:(ℂ∗)n→ℝns^{-1}\text{Log}:(\mathbb{C}^{*})^{n}\to\mathbb{R}^{n}, the function uu pulls back to a psh function on {|log|zi||<s}\{|\log|z_{i}||<s\}. Then the real MA measure of uu is related to the pushforward of the complex MA measure of u∘s−1​Logu\circ s^{-1}\text{Log} by

M​A​(u)=snπn​n!​(s−1​Log)∗​(−1​∂∂¯​(u∘s−1​Log))n.MA(u)=\frac{s^{n}}{\pi^{n}n!}(s^{-1}\text{Log})_{*}(\sqrt{-1}\partial\bar{\partial}(u\circ s^{-1}\text{Log}))^{n}.
00SM

Proof. If uu is smooth, then

M​A​(u)​(K)=∫Kdet(D2​u)​d​x1​…​d​xn=snπn​n!​∫(s−1​Log)−1​(K)(−1​∂∂¯​(u∘s−1​Log))n.MA(u)(K)=\int_{K}\det(D^{2}u)dx_{1}\ldots dx_{n}=\frac{s^{n}}{\pi^{n}n!}\int_{(s^{-1}\text{Log})^{-1}(K)}(\sqrt{-1}\partial\bar{\partial}(u\circ s^{-1}\text{Log}))^{n}.

Since u∈C0u\in C^{0}, and both the real and complex MA operators are weakly continuous with respect to C0C^{0}-limits, this equality passes to general uu. ∎

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