ScalingStacks

Verified tagged author-source HTML · 1912.02360v1 · cited publication edition alignment unverified.

00QU

Proof. The if direction is because the asymptotic growth condition (18) implies the gradient of uu must be contained in Δ\Delta.

For the only if direction, we apply the Legendre transform:

u∗​(p)=supx∈∂Δλ∨{⟨x,p⟩−u⁡(x)},p∈Δ,u^{*}(p)=\sup_{x\in\partial\Delta_{\lambda}^{\vee}}\{\langle x,p\rangle-u(x)\},\quad p\in\Delta,

and consider a version of the double Legendre transform

u∗⁣∗​(x)=supp∈Δ{⟨x,p⟩−u∗​(p)}.u^{**}(x)=\sup_{p\in\Delta}\{\langle x,p\rangle-u^{*}(p)\}.

Clearly u∗⁣∗u^{**} is convex, and admissible by the boundedness of u∗u^{*}, and u∗⁣∗​(x)≤u⁡(x)u^{**}(x)\leq u(x) on ∂Δλ∨\partial\Delta_{\lambda}^{\vee} because

⟨x,p⟩−u∗​(p)≤u⁡(x),∀p∈Δ.\langle x,p\rangle-u^{*}(p)\leq u(x),\quad\forall p\in\Delta.

Our characterisation precisely ensures u∗⁣∗​(x)≥u⁡(x)u^{**}(x)\geq u(x) on ∂Δλ∨\partial\Delta_{\lambda}^{\vee}. Then u∗⁣∗u^{**} provides the canonical extension. ∎

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