ScalingStacks

Verified tagged author-source HTML · 1912.02360v1 · cited publication edition alignment unverified.

00Q5

Proof. (sketch) Let x=Logs​(z)x=\text{Log}_{s}(z) and let m′∈Δℤm^{\prime}\in\Delta_{\mathbb{Z}} saturate the maximum for Lλ​(x)L_{\lambda}(x). Applying Logs\text{Log}_{s} to the inequality

|es​λ​(m′)zm′|=|−∑m≠m′amam′es​λ​(m)zm|≤Cmaxm≠m′{es​λ​(m)|zm|},|e^{s\lambda(m^{\prime})}z^{m^{\prime}}|=|-\sum_{m\neq m^{\prime}}\frac{a_{m}}{a_{m^{\prime}}}e^{s\lambda(m)}z^{m}|\leq C\max_{m\neq m^{\prime}}\{e^{s\lambda(m)}|z^{m}|\},

we see

Lλ​(x)=⟨x,m′⟩+λ⁡(m′)≤maxm≠m′⁡{⟨x,m⟩+λ⁡(m)}+Cs,L_{\lambda}(x)=\langle x,m^{\prime}\rangle+\lambda(m^{\prime})\leq\max_{m\neq m^{\prime}}\{\langle x,m\rangle+\lambda(m)\}+\frac{C}{s},

so distℝn+1​(x,𝒜λ∞)≤Cs\text{dist}_{\mathbb{R}^{n+1}}(x,\mathcal{A}_{\lambda}^{\infty})\leq\frac{C}{s}. The other inequality of the claim can be proved by constructing local models of XsX_{s} in regions whose Logs\text{Log}_{s}-images are close to x∈𝒜λ∞x\in\mathcal{A}_{\lambda}^{\infty}, and then use the implicit function theorem to show XsX_{s} is a small perturbation of these local models. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.