ScalingStacks

Proof. [055R]

Original official author HTML, exact retained edition. Historical TeX conversion verdicts remain unchanged. Cited-edition alignment and mathematical self-containment are not assessed.

Complete original source context · Original author HTML

Proof.

We know 𝒳^\widehat{\mathcal{X}} is isomorphic to 𝒳\mathcal{X} away from D×{0}D\times\{0\}, so it suffices to consider around a point (x,0)(x,0) where f1​(x)=f2​(x)=0f_{1}(x)=f_{2}(x)=0. Locally in an affine chart {s1≠0}\{s_{1}\neq 0\}, 𝒳^\widehat{\mathcal{X}} is then cut out by the equations

(7.21) {f2​(u)​ζ3=td1;f1​(u)​ζ3=td2​ζ2;ζ2+ζ32​f​(u)=0;f2​(u)​ζ2=td1−d2​f1​(u);td2​ζ3​f​(u)+f1​(u)=0.\begin{cases}f_{2}(u)\zeta_{3}=t^{d_{1}};\\ f_{1}(u)\zeta_{3}=t^{d_{2}}\zeta_{2};\\ \zeta_{2}+\zeta_{3}^{2}f(u)=0;\\ f_{2}(u)\zeta_{2}=t^{d_{1}-d_{2}}f_{1}(u);\\ t^{d_{2}}\zeta_{3}f(u)+f_{1}(u)=0.\end{cases}

These can be reduced to two equations on the coordinates uu, tt and ζ3\zeta_{3}, given by

(7.22) {f2​(u)​ζ3−td1=0td2​ζ3​f​(u)+f1​(u)=0.\begin{cases}f_{2}(u)\zeta_{3}-t^{d_{1}}=0\\ t^{d_{2}}\zeta_{3}f(u)+f_{1}(u)=0.\end{cases}

By our assumption (iii) locally we may use v1=f1​(u)v_{1}=f_{1}(u) and v2=f2​(u)v_{2}=f_{2}(u) to replace u1,u2u_{1},u_{2} (say) as local holomorphic coordinates on a neighborhood of xx in ℂ​ℙn+1\mathbb{C}\mathbb{P}^{n+1}. Then it is easy to see the corresponding subvariety is smooth if ζ3≠0\zeta_{3}\neq 0, and has transversal Ad1−1A_{d_{1}-1} singularities along D1D_{1}. So this gives the local description of 𝒳^\widehat{\mathcal{X}} in a neighborhood of D1D_{1}. Similarly on {s2≠0}\{s_{2}\neq 0\} we also know the space is smooth except with transversal Ad2−1A_{d_{2}-1} singularities along D2D_{2}.

On {s3≠0}\{s_{3}\neq 0\}, we use u,t,ζ1,ζ2u,t,\zeta_{1},\zeta_{2} as coordinates, and we get the constraint equations

(7.23) {ζ1​ζ2+f⁡(u)=0,f2​(u)−td1​ζ1=0,f1​(u)−td2​ζ2=0.\begin{cases}\zeta_{1}\zeta_{2}+f(u)=0,\\ f_{2}(u)-t^{d_{1}}\zeta_{1}=0,\\ f_{1}(u)-t^{d_{2}}\zeta_{2}=0.\end{cases}

We only need to consider the points where ζ1=ζ2=t=0\zeta_{1}=\zeta_{2}=t=0, so in particular we also have f⁡(u)=0f(u)=0. At such a point, the differentials of these three equations are (∇f​(u),∇f2​(u),∇f1​(u))(\nabla f(u),\nabla f_{2}(u),\nabla f_{1}(u)). This is non-zero by our assumption (iv). ∎

Original mathematics by the credited authors. Source-backed reader collection; mathematical self-containment is not assessed.