Lemma 6.1 (Implicit function theorem) . [054T] Original official author HTML, exact retained edition. Historical TeX conversion verdicts remain unchanged. Cited-edition alignment and mathematical self-containment are not assessed.
Source coverage notes Source fidelity gap: the original arXiv HTML omits an author TeX footnote attached to equation e:def-omega, including its reference to Remark r:error-function. The retained HTML is preserved as published; the original author TeX remains available. TeX correspondence is not complete. Complete original source context Β· Original author HTML
Lemma 6.1 (Implicit function theorem).
Let β± : π β π
\mathscr{F}:\mathfrak{A}\to\mathfrak{B} be a map between two Banach spaces such that for all π― β π \bm{v}\in\mathfrak{A} ,
(6.2)
β± β‘ ( π ) β β± β‘ ( π ) = β β‘ ( π ) + π© β‘ ( π ) , \mathscr{F}(\bm{v})-\mathscr{F}(\bm{0})=\mathscr{L}(\bm{v})+\mathscr{N}(\bm{v}),
where the operator β : π β π
\mathscr{L}:\mathfrak{A}\to\mathfrak{B} is linear and the operator π© : π β π
\mathscr{N}:\mathfrak{A}\to\mathfrak{B} satisfies π© β‘ ( π ) = π \mathscr{N}(\bm{0})=\bm{0} . Additionally we assume the following properties:
(1)
(Bounded inverse) β : π β π
\mathscr{L}:\mathfrak{A}\to\mathfrak{B} is an isomorphism and there is some constant C L > 0 C_{L}>0 such that
(6.3)
β β β 1 β o β p β€ C L , \|\mathscr{L}^{-1}\|_{op}\leq C_{L},
where β β 1 \mathscr{L}^{-1} is the inverse of β \mathscr{L} .
(2)
There exists a constant C N > 0 C_{N}>0 and there is some r 0 β ( 0 , 1 2 β C L β C N ) r_{0}\in(0,\frac{1}{2C_{L}C_{N}}) satisfying the following:
(a)
(Controlled nonlinear error) for all π 1 , π 2 β B r 0 β ( π ) Β― β π \bm{v}_{1},\bm{v}_{2}\in\overline{B_{r_{0}}(\bm{0})}\subset\mathfrak{A} ,
(6.4)
β π© β‘ ( π 1 ) β π© β‘ ( π 2 ) β π
β€ C N β
r 0 β
β π 1 β π 2 β π . \|\mathscr{N}(\bm{v}_{1})-\mathscr{N}(\bm{v}_{2})\|_{\mathfrak{B}}\leq C_{N}\cdot r_{0}\cdot\|\bm{v}_{1}-\bm{v}_{2}\|_{\mathfrak{A}}.
(b)
(Controlled initial error) β± β‘ ( π ) \mathscr{F}(\bm{0})
is effectively controlled as follows,
(6.5)
β β± β‘ ( π ) β π
β€ r 0 4 β C L . \|\mathscr{F}(\bm{0})\|_{\mathfrak{B}}\leq\frac{r_{0}}{4C_{L}}.
Then the equation β± β‘ ( π± ) = π \mathscr{F}(\bm{x})=\bm{0} has a unique solution π± β B r 0 β ( π ) \bm{x}\in B_{r_{0}}(\bm{0}) with the estimate
(6.6)
β π β π β€ 2 β C L β
β β± β‘ ( π ) β π
. \|\bm{x}\|_{\mathfrak{A}}\leq 2C_{L}\cdot\|\mathscr{F}(\bm{0})\|_{\mathfrak{B}}.