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Remark 5.2.4 . [053L]

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Remark 5.2.4.

The homogeneous equation (5.17) was studied by the authors in the special case n=dimℂ(𝒞n)=2n=\dim_{\mathbb{C}}(\mathcal{C}^{n})=2. When jk=0j_{k}=0, (5.17) has standard solutions given by exponential functions. When jk>0j_{k}>0, the transformation was chosen as

(5.28) {y=jk12⋅zn2uk​(z)=e−jk​zn2⋅Q⁡(jk12⋅zn2).\begin{cases}y=j_{k}^{\frac{1}{2}}\cdot z^{\frac{n}{2}}\\ u_{k}(z)=e^{-\frac{j_{k}z^{n}}{2}}\cdot Q(j_{k}^{\frac{1}{2}}\cdot z^{\frac{n}{2}}).\end{cases}

We refer the readers to Section 4 of [HSVZ18] for more details. In the special case n=2n=2, Q⁡(y)Q(y) is an Hermite function which satisfies the Hermite differential equation

(5.29) d2​Q​(y)d​y2−2​y​d​Q​(y)d​y−2​(h+1)​Q​(y)=0.\frac{d^{2}Q(y)}{dy^{2}}-2y\frac{dQ(y)}{dy}-2(h+1)Q(y)=0.

The key tool to prove the estimates for QQ essentially relies on its integral representation formula. However, when n>2n>2, if we perform the transformation as (5.28) then the resulting equation for QQ is more complicated to study. It turns out the transformation (5.25) is a more suitable choice.

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