ScalingStacks

Example 3.106 . [02P0]

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Example 3.106.

When the function ff is differentiable or piecewise affine, the measurable function f∨∘∂ff^{\vee}\circ\partial f can be made explicit.

  1. (1)

    Let f∈𝒞2​(Nℝ)f\in{\mathcal{C}}^{2}(N_{\mathbb{R}}). Proposition 3.94 and the change of variables formula imply g∘∂f=g∘∇fg\circ\partial f=g\circ\nabla f. For the particular case when g=f∨g=f^{\vee}, Theorem 3.52(4) implies, for u∈Nℝu\in N_{\mathbb{R}},

    f∨∘∂f⁡(u)=⟨∇f​(u),u⟩−f⁡(u).f^{\vee}\circ\partial f(u)=\langle\nabla f(u),u\rangle-f(u).
  2. (2)

    Let ff a piecewise affine concave function on NℝN_{\mathbb{R}}. By Proposition 3.95, ℳM​(f){\mathcal{M}}_{M}(f) is supported in the finite set Π​(f)0\Pi(f)^{0} and so is ℳM,g​(f){\mathcal{M}}_{M,g}(f). For v∈Π​(f)0v\in\Pi(f)^{0} write v∗∈Π​(f∨)nv^{*}\in\Pi(f^{\vee})^{n} for the dual polyhedron. Then g∘∂f⁡(v)=1volM⁡(v∗)​∫v∗g​d​volMg\circ\partial f(v)=\frac{1}{\operatorname{vol}_{M}(v^{*})}\int_{v^{*}}g\,\text{\rm d}\operatorname{vol}_{M}, which implies

    f∨∘∂f⁡(v)=1volM⁡(v∗)​∫v∗⟨x,v⟩​d​volM−f⁡(v).f^{\vee}\circ\partial f(v)=\frac{1}{\operatorname{vol}_{M}(v^{*})}\int_{v^{*}}\langle x,v\rangle\,\text{\rm d}\operatorname{vol}_{M}-f(v).

    The function f∨∘∂ff^{\vee}\circ\partial f is defined as a ℳM​(f){\mathcal{M}}_{M}(f)-measurable function. Therefore, only its values at the points v∈Π​(f)0v\in\Pi(f)^{0} are well defined. Nevertheless, we can extend the function f∨∘∂ff^{\vee}\circ\partial f to the whole NℝN_{\mathbb{R}} by writing

    f∨∘∂f⁡(u)=1volμ⁡(∂f⁡(u))​∫∂f⁡(u)⟨x,u⟩​d​μ−f⁡(u)f^{\vee}\circ\partial f(u)=\frac{1}{\operatorname{vol}_{\mu}(\partial f(u))}\int_{\partial f(u)}\langle x,u\rangle\,\text{\rm d}\mu-f(u)

    for any Haar measure μ\mu on the affine space determined by ∂f⁡(u)\partial f(u).

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