ScalingStacks

Proof. [02IZ]

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Proof.

Let ss be a local section of LanL^{{\text{\rm an}}} defined on a point p∈Xanp\in X^{{\text{\rm an}}}. Let π’°βŠ‚π’³{\mathcal{U}}\subset{\mathcal{X}} be a trivializing open neighbourhood of red𝒳⁑(p){\operatorname{red}}_{{\mathcal{X}}}(p), the reduction of pp with respect to the model 𝒳{\mathcal{X}}, and Οƒ\sigma a generator of β„’|𝒰{\mathcal{L}}|_{{\mathcal{U}}}. Let Ξ»\lambda be an analytic function on (π’°βˆ©X)an({\mathcal{U}}\cap X)^{{\text{\rm an}}} such that sβŠ—e=λ​σs^{\otimes e}=\lambda\sigma.

We have that red𝒳′⁑(p)=fβˆ’1​(red⁑(p)){\operatorname{red}}_{{\mathcal{X}}^{\prime}}(p)=f^{-1}({\operatorname{red}}(p)) and 𝒰′:=fβˆ’1​(𝒰){\mathcal{U}}^{\prime}:=f^{-1}({\mathcal{U}}) is a trivializing open set of β„’β€²βŠ—e{\mathcal{L}}^{\prime\otimes e} with generator fβˆ—β€‹ΟƒβŠ—eβ€²f^{*}\sigma^{\otimes e^{\prime}}. Then sβŠ—e​eβ€²=Ξ»e′​fβˆ—β€‹ΟƒβŠ—eβ€²s^{\otimes ee^{\prime}}=\lambda^{e^{\prime}}f^{*}\sigma^{\otimes e^{\prime}} on (π’°β€²βˆ©X)an=(π’°βˆ©X)an({\mathcal{U}}^{\prime}\cap X)^{{\text{\rm an}}}=({\mathcal{U}}\cap X)^{{\text{\rm an}}}. Now the proposition follows directly from Definition 2.17. ∎

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