Appendix A Berkovich spaces over Banach rings [018B]
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Appendix A Berkovich spaces over Banach rings
In this appendix we review the construction of the analytification of a scheme of finite type defined over a Banach ring. The main reference for this is [Berk09]; see also [Poi10, Poi13a, Jon16]. For suitable choices of Banach rings, this leads to spaces that contain both Archimedean and non-Archimedean data.
A.1. Berkovich spectra
Let be a Banach ring, that is, a commutative ring that is complete with respect to a submultiplicative norm . The Berkovich spectrum is the set of all bounded multiplicative seminorms on . In other words, a point corresponds to a function such that , , and for . The spectrum is a nonempty, compact Hausdorff space with respect to the topology of pointwise convergence.
For , denote by the kernel of . This is a prime ideal of , and defines a multiplicative norm on . The completion of the fraction field of with respect to this norm is a valued field . We write for the image of in ; then . The assignment yields a map that is continuous for the Zariski topology .
Example A.1.
If is a valued field (i.e. a field with a multiplicative norm), then is a singleton.
Example A.2.
When is a complex Banach algebra, the Gelfand-Mazur Theorem implies that the Berkovich spectrum agrees with the maximal ideal spectrum.
A.2. Analytification of a scheme
To any scheme of finite type over a Banach ring , Berkovich associates an analytification99 9 We use the term analytification even though we shall only consider as a topological space. In particular, only depends on the reduced scheme structure of . , a locally compact topological space with a continuous morphism , defined as follows.
When is affine, with a finitely generated -algebra, is defined as the set of multiplicative seminorms on whose restriction to is bounded by the given norm on , i.e. belongs to . The topology on is the weakest one for which is continuous for every .
In the general case, the analytification is defined by gluing together the analytifications of an affine open cover, and yields a covariant functor . If is an open (resp. closed) embedding, then so is . If is surjective, then so is .
The topological space is Hausdorff (resp. compact) if is separated (resp. projective). The assignment above globalizes to a continuous map
where is equipped with the Zariski topology.
When is a valued field, it is more common to write instead of [Berk90].
Example A.3.
For , the Gelfand-Mazur theorem shows that coincides with the usual analytification of , i.e. the set of complex points of endowed with the euclidean topology.
A.3. The hybrid norm on
Denote by the Banach field , where the hybrid norm is defined as
with the trivial absolute value and the usual absolute value.
The elements of the Berkovich spectrum are of the form for , interpreted as the trivial absolute value for . This yields a homeomorphism .
A.4. Hybrid geometry over
If is a scheme of finite type over , we denote by its analytification with respect to the usual absolute value , by its analytification with respect to the trivial absolute value, and by its analytification with respect to the hybrid norm .
From the structure morphism we obtain a continuous map . The fiber is equal to the analytification of with respect to the multiplicative norm on . In particular, we have canonical identifications and . For , the fiber is also homeomorphic to . In fact, we have a a homeomorphism
see [Berk09, Lemma 2.1].
A.5. The hybrid circle
Now consider the hybrid circle of radius , that is, . By [Poi10, Prop 2.1.1], this is compact and realized as the Berkovich spectrum of the Banach ring
Since , every defines a continuous function on the punctured closed disc that is holomorphic on and meromorphic at 0.
Proposition A.4.
There is a homeomorphism , that maps to the seminorm on defined by
| (A.1) |
and via which the map is given by .
Proof.
The map given by (A.1) is clearly well defined. It is also continuous on . To prove continuity at , we note that for each , we can write , where is a continuous function on that is holomorphic on with . As a consequence, we get .
Now, for each , can be identified with the circle of radius with respect to the absolute value , while is the non-Archimedean absolute value on . This proves that the map above is bijective, and hence a homeomorphism by compactness. ∎
Remark A.5.
When , the identity gives a bounded map from to , and is the fraction field of , i.e. the ring of meromorphic germs at the origin of .
A.6. Geometry over the hybrid circle
Let now be a scheme of finite type over . We will associate to three kinds of analytic spaces.
First, since is obtained by gluing together finitely many affine schemes cut out by polynomials with coefficients holomorphic on and meromorphic at , we can associate to in a functorial way a complex analytic space over , which we call its holomorphic analytification.
Second, since is contained in , we may also consider the base change and its non-Archimedean analytification with respect to the non-Archimedean absolute value on .
Third, we denote by the analytification of as a scheme of finite type over the Banach ring , and call it the hybrid analytification of . In view of Proposition A.4, it comes with a continuous structure map
Recall further that is locally compact, Hausdorff if is separated, and compact if is proper over . The discussion above implies:
Lemma A.6.
We have canonical homeomorphisms
| (A.2) |
compatible with the projection to .
In §4 we give a topological description of .