A.5. The hybrid circle [018J]
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A.5. The hybrid circle
Now consider the hybrid circle of radius ,
that is, .
ByΒ [Poi10, Prop 2.1.1], this is compact and
realized as the Berkovich spectrum of the Banach ring
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Since ,
every defines a continuous function on the
punctured closed disc that is holomorphic on
and meromorphic at 0.
Proposition A.4.
There is a homeomorphism ,
that maps to the seminorm on defined by
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(A.1) |
and via which the map is given by
.
Proof.
The map given byΒ (A.1) is
clearly well defined. It is also continuous on .
To prove continuity at , we note that for
each , we can write ,
where is a continuous function on that is holomorphic
on with .
As a consequence, we get
.
Now, for each ,
can be identified with the circle of radius with respect to the
absolute value , while is the
non-Archimedean absolute value on .
This proves that the map above is bijective,
and hence a homeomorphism by compactness.
β
Remark A.5.
When , the identity gives a bounded map from to ,
and is the fraction field of , i.e. the ring of
meromorphic germs at the origin of .