Démonstration. [01JI]
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Démonstration.
One has to show that for any continuous function with compact support contained in
By Gubler’s theorem, the space of smooth functions is dense in the space of smooth functions on . Using the fact that the maximum and the minimum of smooth functions are still smooth, one proves that the space of smooth functions with compact support contained in is dense in the space of continuous functions with compact support contained in , for the topology of uniform convergence. We thus may assume that is smooth, with compact support contained in . Finally, we may also assume that the metric on the line bundles are smooth.
We may argue locally and assume that has a meromorphic section whose divisor is disjoint from . Up to shrinking again, we may assume that there exists a sequence of rational functions without zeroes nor poles on such that .
According to Prop. 1.3.2, one has
The first term vanishes because and the support of are disjoint. The second is the limit of
Using the fact that is empty and applying the same computation, the term of index equals
where is the trivial metrized line bundle , and its meromorphic section replacing . But this integral is zero, by definition of the measures associated to smooth metrized line bundles. ∎