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The arithmetic Hodge index theorem [01KF]

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The arithmetic Hodge index theorem

Let XX be a projective smooth curve over FF, let L¯\overline{L} be a line bundle of degree 00 on XX, with an admissible metric. Let L¯0\overline{L}_{0} be the same line bundle with the canonical metric : if XX has genus ≥1\geq 1, this is the metric induced by an embedding of XX into its Jacobian, if XX is of genus 00, then L¯0\overline{L}_{0} is the trivial metrized line bundle. The metrized line bundle L¯⊗L¯0−1\overline{L}\otimes\overline{L}_{0}^{-1} is the trivial line bundle, together with an admissible metric which is given by a function fvf_{v} at the place vv of FF.

A formula of Faltings–Hriljac expresses (c^1​(L¯0)2|X)({\widehat{c}}_{1}(\overline{L}_{0})^{2}|X) as twice minus the Néron–Tate height of the point of JJ corresponding to LL. More generally,

(c^1​(L¯)2|X)=−2​h^NT​([L])+∑v∈M⁡(F)𝒟⁡(fv),({\widehat{c}}_{1}(\overline{L})^{2}|X)=-2\widehat{h}_{\mathrm{NT}}([L])+\sum_{v\in M(F)}\mathscr{D}(f_{v}),

where for each v∈M⁡(F)v\in M(F),

𝒟⁡(fv)=∫Xvfv​ddc⁡(fv)\mathscr{D}(f_{v})=\int_{X_{v}}f_{v}\mathop{\mathrm{d}\mathrm{d}^{c}}(f_{v})

is the Dirichlet energy of fvf_{v}. This is a non positive quadratic form which vanishes if and only if fvf_{v} is constant. For more details, I refer to [15] at archimedean places and [51] at ultrametric places. (When XX has genus 00, L≃𝒪XL\simeq\mathscr{O}_{X} and the term h^NT​([L])\widehat{h}_{\mathrm{NT}}([L]) has to be interpreted as 00.)

As a consequence, (c^1​(L¯)2|X)≤0({\widehat{c}}_{1}(\overline{L})^{2}|X)\leq 0. Let us analyse the case of equality. Since they are nonpositive, all terms in the formula above have to vanish. Consequently, [L][L] is a torsion point in the Jacobian, and all functions fvf_{v} are constant. We will say that some power of L¯\overline{L} is constant

Proposition 3.4.1.

Let FF be a number field, let XX be a projective smooth curve over FF. Let L¯\overline{L} and M¯\overline{M} be two admissible metrized line bundles over XX. Assume that deg⁡(L)=ℓ\deg(L)=\ell, deg⁡(M)=m\deg(M)=m are positive. and (c^1​(L¯)2|X)=(c^1​(M¯)2|X)=0({\widehat{c}}_{1}(\overline{L})^{2}|X)=({\widehat{c}}_{1}(\overline{M})^{2}|X)=0. Then, the essential minimum of L¯⊗M¯\overline{L}\otimes\overline{M} satisfies the following inequality :

e⁡(L¯⊗M¯)≥−12​(ℓ+m)​ℓ​m​(c^1​(m​L¯−ℓ​M¯)2|X).e(\overline{L}\otimes\overline{M})\geq-\frac{1}{2(\ell+m)\ell m}({\widehat{c}}_{1}(m\overline{L}-\ell\overline{M})^{2}|X).

Moreover, the right hand side of this inequality is always nonnegative and vanishes if and only if some power of L¯m⊗M¯−ℓ\overline{L}^{m}\otimes\overline{M}^{-\ell} is constant.

Démonstration.

By Zhang’s inequality (see [18]), one has

e⁡(L¯+M¯)≥12​(ℓ+m)​(c^1​(L¯+M¯)2|X).e(\overline{L}+\overline{M})\geq\frac{1}{2(\ell+m)}({\widehat{c}}_{1}(\overline{L}+\overline{M})^{2}|X).

Since (c^1​(L¯)2|X)=(c^1​(M¯)2|X)=0({\widehat{c}}_{1}(\overline{L})^{2}|X)=({\widehat{c}}_{1}(\overline{M})^{2}|X)=0 by assumption, we observe that

(c^1​(L¯+M¯)2|X)=2​(c^1​(L¯)​c^1​(M¯)|X)=−1ℓ​m​(c^1​(m​L¯−ℓ​M¯)2|X).({\widehat{c}}_{1}(\overline{L}+\overline{M})^{2}|X)=2({\widehat{c}}_{1}(\overline{L}){\widehat{c}}_{1}(\overline{M})|X)=-\frac{1}{\ell m}({\widehat{c}}_{1}(m\overline{L}-\ell\overline{M})^{2}|X).

This shows the first claim.

Since m​LmL and ℓ​M\ell M have the same degree, viz. ℓ​m\ell m, the rest of the proposition follows from the negativity properties of the height recalled above. ∎

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