ScalingStacks

Démonstration. [01JI]

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Démonstration.

One has to show that for any continuous function φ\varphi with compact support contained in U\mathrm{U}

∫Xφ​c1​(L¯1)​…​c1​(L¯k)​δZ=0.\int_{\mathrm{X}}\varphi\,c_{1}(\overline{L}_{1})\dots c_{1}(\overline{L}_{k})\delta_{\mathrm{Z}}=0.

By Gubler’s theorem, the space of smooth functions is dense in the space of smooth functions on X\mathrm{X}. Using the fact that the maximum and the minimum of smooth functions are still smooth, one proves that the space of smooth functions with compact support contained in U\mathrm{U} is dense in the space of continuous functions with compact support contained in U\mathrm{U}, for the topology of uniform convergence. We thus may assume that φ\varphi is smooth, with compact support contained in U\mathrm{U}. Finally, we may also assume that the metric on the line bundles L¯2,…,L¯k\overline{L}_{2},\dots,\overline{L}_{k} are smooth.

We may argue locally and assume that L1L_{1} has a meromorphic section ss whose divisor div⁡(s)\operatorname{div}(s) is disjoint from U\mathrm{U}. Up to shrinking U\mathrm{U} again, we may assume that there exists a sequence (un)(u_{n}) of rational functions without zeroes nor poles on U\mathrm{U} such that log⁡‖s‖=limlog⁡|un|1/n\log\left\|{s}\right\|=\lim\log\left|{u_{n}}\right|^{1/n}.

According to Prop. 1.3.2, one has

∫Xφ​c1​(L¯1)​…​c1​(L¯k)​δZ=∫Xφ​c1​(L¯2)​…​c1​(L¯k)​δdiv⁡(s|Z)+∫Xlog⁡‖s‖−1​ddc⁡φ​c1​(L¯2)​…​c1​(L¯k)​δZ,\int_{\mathrm{X}}\varphi\,c_{1}(\overline{L}_{1})\dots c_{1}(\overline{L}_{k})\delta_{\mathrm{Z}}\\ =\int_{\mathrm{X}}\varphi c_{1}(\overline{L}_{2})\dots c_{1}(\overline{L}_{k})\delta_{\operatorname{div}(s|_{\mathrm{Z}})}+\int_{\mathrm{X}}\log\left\|{s}\right\|^{-1}\mathop{\mathrm{d}\mathrm{d}^{c}}\varphi c_{1}(\overline{L}_{2})\dots c_{1}(\overline{L}_{k})\delta_{\mathrm{Z}},

The first term vanishes because div⁡(s|Z)\operatorname{div}(s|_{\mathrm{Z}}) and the support of φ\varphi are disjoint. The second is the limit of

∫Xlog|un|−1/nddcφc1(L¯)k−1δZ.\int_{\mathrm{X}}\log\left|{u_{n}}\right|^{-1/n}\mathop{\mathrm{d}\mathrm{d}^{c}}\varphi c_{1}(\overline{L})^{k-1}\delta_{\mathrm{Z}}.

Using the fact that div⁡(un)∩U\operatorname{div}(u_{n})\cap\mathrm{U} is empty and applying the same computation, the term of index nn equals

1n​∫Xφ​c1​(M¯n)​c1​(L¯2)​…​c1​(L¯k)​δZ.\frac{1}{n}\int_{\mathrm{X}}\varphi\,c_{1}(\overline{M}_{n})c_{1}(\overline{L}_{2})\dots c_{1}(\overline{L}_{k})\delta_{\mathrm{Z}}.

where M¯n\overline{M}_{n} is the trivial metrized line bundle 𝒪X\mathscr{O}_{X}, and its meromorphic section unu_{n} replacing ss. But this integral is zero, by definition of the measures associated to smooth metrized line bundles. ∎

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