Proof of Proposition 2.1 . [0158]
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Proof of Proposition 2.1.
Pick an open
cover as in Lemma 2.2, and denote by
the corresponding maps.
Set , and pick a partition of unity
subordinate to .
We claim that for each there exists an open neighborhood
of
and a face of such that
|
|
|
for any . Indeed, using (2.3) it is easy to see that
|
|
|
satisfies this property. By convexity of , it follows that
is well-defined on
, and hence yields a continuous map
.
The last property is a direct consequence of (2.1).
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