ScalingStacks

003S

Proposition 6.7. Assume ‖ϕ‖C0\left\lVert\phi\right\rVert_{C^{0}} has a uniform bound independent of tt. Then after shrinking UU by a small amount independent of tt, we have

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    The convex function ϕ¯\bar{\phi} has a Lipschitz bound |ϕ¯​(x)−ϕ¯​(x′)|≤C​|x−x′|.|\bar{\phi}(x)-\bar{\phi}(x^{\prime})|\leq C|x-x^{\prime}|.

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    There is an upper bound ϕ−ϕ¯≤C|log⁡|t||1/2\phi-\bar{\phi}\leq\frac{C}{|\log|t||^{1/2}}.

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    On each logarithmic dyadic scale Ua={ai≤log|zi|≤2ai,∀i}⊂UU_{a}=\{a_{i}\leq\log|z_{i}|\leq 2a_{i},\forall i\}\subset U, the L1L^{1}-integral

    ∫Ua|ϕ−ϕ¯|​∏−1​d​log⁡zi∧𝑑log⁡zi¯≤C|log⁡|t||1/2.\int_{U_{a}}|\phi-\bar{\phi}|\prod\sqrt{-1}d\log z_{i}\wedge d\overline{\log z_{i}}\leq\frac{C}{|\log|t||^{1/2}}.
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    There is an improved Skoda inequality with uniform constants α,C\alpha,C independent of tt:

    ∫Ue−α​|log⁡|t||1/2​(ϕ−ϕ¯)​d​μt≤C.\int_{U}e^{-\alpha|\log|t||^{1/2}(\phi-\bar{\phi})}d\mu_{t}\leq C.
003T

Proof. (Sketch)

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    Bounded convex functions automatically have Lipschitz bound on slightly shrinked convex domains.

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    The second item follows from a slightly tricky application of mean value inequality for subharmonic functions, cf. [52, section 4.3].

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    The third item is because the function ϕ−ϕ¯\phi-\bar{\phi} has mean value zero, so an upper bound implies an L1L^{1}-bound, cf. [52, section 4.3].

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    One first apply the basic Skoda estimate Thm. 4.2 to the function ϕ\phi on each logarithmic dyadic scale, where ϕ¯\bar{\phi} is almost constant by the Lipschitz bound. Then we sum over all the logarithmic dyadic scales (cf. [52, section 4.6]).

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