ScalingStacks

003Q

Lemma 6.6. [52, Lemma 4.3] The fibrewise TnT^{n} average function

ϕ¯​(x1,…​xn)=1(2​π)n​∫Tnϕ⁡(ex1​log⁡|t|+i​θ1,…​exn​log⁡|t|+i​θn)​d​θ1​…​d​θn\bar{\phi}(x_{1},\ldots x_{n})=\frac{1}{(2\pi)^{n}}\int_{T^{n}}\phi(e^{x_{1}\log|t|+i\theta_{1}},\ldots e^{x_{n}\log|t|+i\theta_{n}})d\theta_{1}\ldots d\theta_{n}

is a convex function in the variables x1,…​xnx_{1},\ldots x_{n}.

003R

Proof. Since the function ϕ¯\bar{\phi} is an average of psh functions, it is psh as a TnT^{n}-invariant function on Logt−1​(U)\text{Log}_{t}^{-1}(U). Such functions correspond to convex functions downstairs. ∎

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