Proof. [04LV]
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Proof.
The proof follows the same lines of Lemma 7.6. Assume that has been constructed with Theorem 6.19. In particular the wall consists of the union of three disjoint sets, denoted , and . The corresponding components of the seam are , and with corresponding quotients denoted by , and . The invariants of are given by sequences , and . In particular the first order invariants satisfy the integral conditions (60) with and .
Over the same wall and seam , we could define another triple of invariants as follows. Define to be the zero sequence, while and to be sequences whose only non-zero terms are the first order ones, which we define to be
As we saw in Example 6.21, these choices of invariants give rise to a fake stitched fibration which is topologically conjugate to .
Using Theorem 6.19 we now construct a new stitched fibration with the same wall and seam as , but whose invariants interpolate between those of and those of . Let be a small tubular neighborhood of and denote . Assume that is entirely contained in the region in Figure 15 (a) delimited by the dotted lines. In particular we want the ends of to be contained in the white region where is smooth. Let be a smaller open neighborhood of and denote . Let be a cut-off function which is 1 on and on . Define and similarly define and . It follows from Theorem 6.19 that the sequences , and give rise to a stitched Lagrangian fibration which is topologically conjugate to . Moreover and are symplectically conjugate so we can glue to along . This produces a piecewise smooth Lagrangian fibration which is topologically conjugate to , moreover the chosen invariants guarantee that after a change of coordinates on the base satisfies the smoothness condition . ∎