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Proposition 6.5 [03LK]

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Proposition 6.5

Let u,v:ℝ2→ℝu,v:\mathbin{\mathbb{R}}^{2}\rightarrow\mathbin{\mathbb{R}} be solutions of (33). Then there exists a unique function f:ℝ2→ℝf:\mathbin{\mathbb{R}}^{2}\rightarrow\mathbin{\mathbb{R}} with

∂f∂x=u,∂f∂y=vandf(0,0)=0,satisfying∂2f∂x2+(4​(∂f∂x)2+4​y2+a2)1/2​∂2f∂y2=0.\begin{gathered}\frac{\partial f}{\partial x}=u,\quad\frac{\partial f}{\partial y}=v\quad\text{and}\quad f(0,0)=0,\\ \text{satisfying}\quad\frac{\partial^{2}f}{\partial x^{2}}+\Bigl(4\Bigl(\frac{\partial f}{\partial x}\Bigr)^{2}+4y^{2}+a^{2}\Bigr)^{1/2}\frac{\partial^{2}f}{\partial y^{2}}=0.\end{gathered} (39)

Conversely, all solutions of (39) yield solutions of (33).

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