ScalingStacks

Lemma 6.2 [03LH]

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Lemma 6.2

Let 𝐳=(z1,z1,z3)∈N{\bf z}=(z_{1},z_{1},z_{3})\in N, with z1β‰ 0z_{1}\neq 0. Set x=Re(z3)x=\mathop{\rm Re}(z_{3}) and y=Im(z12)y=\mathop{\rm Im}(z_{1}^{2}). Then NN is nonsingular at 𝐳\bf z, and T𝐳​N=⟨𝐩1,𝐩2,𝐩3βŸ©β„,T_{\bf z}N=\langle{\bf p}_{1},{\bf p}_{2},{\bf p}_{3}\rangle_{\scriptscriptstyle\mathbb{R}}, where

𝐩1\displaystyle{\bf p}_{1} =(i​z1,βˆ’i​z1,0),\displaystyle=(iz_{1},-iz_{1},0), (34)
𝐩2\displaystyle{\bf p}_{2} =((2z1)βˆ’1βˆ‚uβˆ‚x(x,y),(2z1)βˆ’1βˆ‚uβˆ‚x(x,y),1+iβˆ‚vβˆ‚x(x,y))and\displaystyle=\bigl((2z_{1})^{-1}{\textstyle\frac{\partial u}{\partial x}}(x,y),(2z_{1})^{-1}{\textstyle\frac{\partial u}{\partial x}}(x,y),1+i{\textstyle\frac{\partial v}{\partial x}}(x,y)\bigr)\quad\text{and} (35)
𝐩3\displaystyle{\bf p}_{3} =((2​z1)βˆ’1​(βˆ‚uβˆ‚y​(x,y)+i),(2​z1)βˆ’1​(βˆ‚uβˆ‚y​(x,y)+i),iβ€‹βˆ‚vβˆ‚y​(x,y)).\displaystyle=\bigl((2z_{1})^{-1}({\textstyle\frac{\partial u}{\partial y}}(x,y)+i),(2z_{1})^{-1}({\textstyle\frac{\partial u}{\partial y}}(x,y)+i),i{\textstyle\frac{\partial v}{\partial y}}(x,y)\bigr). (36)

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