2.1 Special Lagrangian submanifolds in
We begin by defining calibrations and calibrated
submanifolds, following Harvey and Lawson [9].
Definition 2.1 Let be a Riemannian manifold. An oriented
tangent -plane on is a vector subspace of
some tangent space to with , equipped
with an orientation. If is an oriented tangent -plane
on then is a Euclidean metric on , so
combining with the orientation on gives a
natural volume form on , which is a
-form on .
Now let be a closed -form on . We say that
is a calibration on if for every oriented
-plane on we have . Here
for some , and
if . Let be an
oriented submanifold of with dimension . Then
each tangent space for is an oriented
tangent -plane. We say that is a calibrated
submanifold if for all .
It is easy to show that calibrated submanifolds are automatically
minimal submanifolds [9, Th. II.4.2]. Here is the
definition of special Lagrangian submanifolds in , taken
from [9, §III].
Definition 2.2 Let have complex coordinates ,
and define a metric , a real 2-form and a complex -form
on by
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(1) |
Then and are real -forms on . Let
be an oriented real submanifold of of real dimension
. We say that is a special Lagrangian submanifold
of or SL -fold for short, if is calibrated
with respect to , in the sense of Definition 2.1.
As in [10, 11] there is a more general definition of
special Lagrangian -fold involving a phase ,
but we will not use it here. Harvey and Lawson [9, Cor. III.1.11]
give the following alternative characterization of special Lagrangian
submanifolds.
Proposition 2.3
Let be a real -dimensional submanifold
of . Then admits an orientation making it into an
SL submanifold of if and only if
and .
An -dimensional submanifold in is called Lagrangian
if . Thus special Lagrangian submanifolds are
Lagrangian submanifolds satisfying the extra condition that
, which is how they get their name.
Next we give a result characterizing SL 3-planes in ,
which will be useful in §7. Define an anti-bilinear cross
product by
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(2) |
It is equivariant under the -action on . Using this
notation, we prove
Proposition 2.4
Let be linearly independent
over , with . Then
and are linearly independent over , and
is the
unique special Lagrangian -plane in
containing .
Proof. Explicit calculation using (2) shows that
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(3) |
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(4) |
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(5) |
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(6) |
for all . When are
linearly independent and , equation
(3) shows that is orthogonal to
, and (5) that .
Therefore and are linearly
independent.
Also we have by (4), so that
is a
Lagrangian 3-plane. Then (6) shows that
is a
special Lagrangian 3-plane, by Proposition 2.7.
It is easy to see that this is the only SL 3-plane in
containing .