ScalingStacks

Proof. [03HI]

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Proof.

Let y=j​zy=\sqrt{j}z and a=2​ya=2y, then by definition,

(4.89) F^=−a28−(t0​(a))2+a​t0​(a)+h​log⁡(t0​(a))\widehat{F}=-\frac{a^{2}}{8}-(t_{0}(a))^{2}+at_{0}(a)+h\log(t_{0}(a))

and

(4.90) U^=−a28−(s0​(a))2−a​s0​(a)+h​log⁡(s0​(a)).\widehat{U}=-\frac{a^{2}}{8}-(s_{0}(a))^{2}-as_{0}(a)+h\log(s_{0}(a)).

We show that F^\widehat{F} is increasing in aa and U^\widehat{U} is decreasing in aa. Indeed,

(4.91) d​F^d​a=−a4+t0​(a)+(−2​t0​(a)+a+ht0​(a))​t0′​(a)=h2+a216≥a4.\displaystyle\frac{d\widehat{F}}{da}=-\frac{a}{4}+t_{0}(a)+\Big(-2t_{0}(a)+a+\frac{h}{t_{0}(a)}\Big)t_{0}^{\prime}(a)=\sqrt{\frac{h}{2}+\frac{a^{2}}{16}}\geq\frac{a}{4}.

So the monotonicity of F^​(z)−η​z\widehat{F}(z)-\eta z immediately follows when z>2​ηz>2\eta. Similarly, the monotonicity of U^+η​z\widehat{U}+\eta z follows from the computation

(4.92) d​U^d​a=−a4−s0​(a)+(−2​s0​(a)−a+hs0​(a))​s0′​(a)=−h2+a216≤−a4.\displaystyle\frac{d\widehat{U}}{da}=-\frac{a}{4}-s_{0}(a)+\Big(-2s_{0}(a)-a+\frac{h}{s_{0}(a)}\Big)s_{0}^{\prime}(a)=-\sqrt{\frac{h}{2}+\frac{a^{2}}{16}}\leq-\frac{a}{4}.

∎

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