ScalingStacks

Proof. [02DI]

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Proof.

Fix u∈P​S​H​(X,ω)u\in PSH(X,\omega) with 0≤u≤10\leq u\leq 1. For δ>0\delta>0 we set t=δ/(1+δ)t=\delta/(1+\delta). Observe that 0≤t≤10\leq t\leq 1 and

{φ−ψ<−s−t}⊂{φ<ψ+δ​u1+δ−s−t}⊂{φ−ψ<−s−tψ}.\{\varphi-\psi<-s-t\}\subset\{\varphi<\frac{\psi+\delta u}{1+\delta}-s-t\}\subset\{\varphi-\psi<-s-t\psi\}.

Set φ~:=(ψ+δ​u)/(1+δ)−s−t∈P​S​H​(X,ω)\tilde{\varphi}:=(\psi+\delta u)/(1+\delta)-s-t\in PSH(X,\omega). Observe that

tn​∫(φ−ψ<−s−t)ωun≤∫(φ−ψ<−s−t)[11+δ​ωψ+δ1+δ​ωu]n≤∫(φ<φ~)[ω+d​dc​φ~]n.t^{n}\int_{(\varphi-\psi<-s-t)}\omega_{u}^{n}\leq\int_{(\varphi-\psi<-s-t)}\left[\frac{1}{1+\delta}\omega_{\psi}+\frac{\delta}{1+\delta}\omega_{u}\right]^{n}\leq\int_{(\varphi<\tilde{\varphi})}[\omega+dd^{c}\tilde{\varphi}]^{n}.

It follows from the comparison principle in class ℰ1​(X,ω){\mathcal{E}}^{1}(X,\omega), that

∫(φ<φ~)[ω+d​dc​φ~]n≤∫(φ<φ~)[ω+d​dc​φ]n≤∫(φ−ψ<−s−t​ψ)[ω+d​dc​φ]n.\int_{(\varphi<\tilde{\varphi})}[\omega+dd^{c}\tilde{\varphi}]^{n}\leq\int_{(\varphi<\tilde{\varphi})}[\omega+dd^{c}\varphi]^{n}\leq\int_{(\varphi-\psi<-s-t\psi)}[\omega+dd^{c}\varphi]^{n}.

Taking the supremum over all u’s yields the desired result. ∎

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