Proof.
Let us remark first, that if , then by volume ratio monotonicity, we have for every that
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(8.52) |
Let from Lemma 8.8 with sufficiently small to satisfy
Theorem 8.3 and Lemmas 8.8, 8.9, 8.10.
After rescaling, it is sufficient to consider a Riemannian manifold with ,
and for every .
Let us begin by efficiently covering by balls such that
the balls in are disjoint.
By the usual doubling argument, there are at most such balls. For each such ball, we
apply Lemma 8.10 in order to produce a collection of balls
such that , , , and
such that if then . Furthermore, if we denote
by ,
the group associated to , then if is the largest integer such that
, then for all
we have
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(8.53) |
Define
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(8.54) |
as the first body region. Then we can write
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(8.55) |
where by using Theorem 8.3, we have that is
diffeomorphic to .
Now to prove the theorem, let us inductively build a decomposition of
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(8.56) |
with the following properties:
- (1)
If then .
- (2)
Each neck is diffeomorphic to
for some .
- (3)
are diffeomorphic to . are either empty or diffeomorphic to .
- (4)
.
- (5)
If , then .
- (6)
We have with ,
and .
- (7)
If is the largest integer such that ,
then for every we have .
Before building the inductive decomposition, let us note that once we have it,
we will have finished the proof.
In fact, all we really need to see is that for some , there are no balls
in the decomposition.
To see this, observe that by the lower volume bound we have the upper order bound
.
By condition (5) above we have by iteration that for each that there is some
such that
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(8.57) |
and in particular this immediately implies the upper bound
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(8.58) |
To prove the inductive decomposition, we begin by noting
that (8.55) provides the basic
case. So let us assume that the
decomposition has been constructed for some ,
and let us build the decomposition for .
First, we use condition (7) and Lemma 8.8 to see that there
exists an open set
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(8.59) |
and a diffeomorphism with .
By Lemma 8.9, there exists a radius
such that
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(8.60) |
for every .
Pick some
efficient covering
of such that the balls in
disjoint. Now apply Lemma 8.10 to each
ball in order to construct
a collection of balls with .
Observe that since there are at most balls in the collection ,
and the application of Lemma 8.10
produces at most balls for each of these, we have at most such balls in total.
If we put
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(8.61) |
we see that and the collection satisfy
the inductive conditions. Specifically,
what is left to check is condition (5). However, by construction, we have
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(8.62) |
which for sufficiently small implies . In particular,
the decomposition
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(8.63) |
satisfies the inductive hypothesis as well, which completes the proof.