ScalingStacks

Verified tagged author-source HTML · 1904.03696v1 · cited publication edition alignment unverified.

00M9

Proof. By assumption, L⊗ML^{\otimes M} is very ample. So V^∙(M)​(L,ϕ)\widehat{V}_{{\scriptscriptstyle\bullet}}^{(M)}(L,\phi), V^∙(M)​(LX|Y,ϕX|Y)\widehat{V}_{{\scriptscriptstyle\bullet}}^{(M)}(L_{X|Y},\phi_{X|Y}) and V^∙(M)​(L|Y,ϕ|Y)\widehat{V}_{{\scriptscriptstyle\bullet}}^{(M)}(L|_{Y},\phi|_{Y}) are affinoid algebras. Since V∙​(L)V_{{\scriptscriptstyle\bullet}}(L) is integral and is finite over V∙(M)​(L)V_{{\scriptscriptstyle\bullet}}^{(M)}(L), by Proposition 2.45, the Banach algebras V^∙​(L,ϕ)\widehat{V}_{{\scriptscriptstyle\bullet}}(L,\phi), V^​(LX|Y,ϕX|Y)\widehat{V}(L_{X|Y},\phi_{X|Y}) and V^∙​(L|Y,ϕ|Y)\widehat{V}_{{\scriptscriptstyle\bullet}}(L|_{Y},\phi|_{Y}) are Banach finite over V^∙(M)​(L,ϕ)\widehat{V}_{{\scriptscriptstyle\bullet}}^{(M)}(L,\phi), V^∙(M)​(LX|Y,ϕX|Y)\widehat{V}_{{\scriptscriptstyle\bullet}}^{(M)}(L_{X|Y},\phi_{X|Y}) and V^∙(M)​(L|Y,ϕ|Y)\widehat{V}_{{\scriptscriptstyle\bullet}}^{(M)}(L|_{Y},\phi|_{Y}) respectively. Hence they are affinoid algebras. ∎

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