ScalingStacks

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Proposition 2.45. Let (B,⦀⋅⦀)(B,\vvvert\mathord{\cdot}\vvvert) be a normed algebra and let ℬ\mathcal{B} be its separated completion. Let AA be a sub-kk-algebra of BB, equipped with the restriction algebra norm of ⦀⋅⦀\vvvert\mathord{\cdot}\vvvert, and let 𝒜\mathcal{A} be the separated completion of (A,⦀⋅⦀)(A,\vvvert\mathord{\cdot}\vvvert). Assume that 𝒜\mathcal{A} is an affinoid algebra. If BB is integral and is finite over AA, then ℬ\mathcal{B} is Banach finite over 𝒜\mathcal{A}. Therefore ℬ\mathcal{B} is an affinoid algebra.

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Proof. By assumption, there exists j∈ℕj\in\mathbb{N} and a homomorphism of kk-algebras and elements {ei}i∈{1,…,j}⊆B\{e_{i}\}_{i\in\{1,\dots,j\}}\subseteq B such that

F:⨁i∈{1,…,j}A→B,1i↦eiF:\bigoplus_{i\in\{1,\dots,j\}}A\rightarrow B,1_{i}\mapsto e_{i}

Moreover, FF is bounded

⦀∑i∈{1,…,j}ai⋅ei⦀≤maxi∈{1,…,j}⦀ai⋅ei⦀≤maxi∈{1,…,j}⦀ei⦀⋅maxi∈{1,…,j}⦀ai⦀\vvvert\sum_{i\in\{1,\dots,j\}}a_{i}\cdot e_{i}\vvvert\leq\max_{i\in\{1,\dots,j\}}\vvvert a_{i}\cdot e_{i}\vvvert\leq\max_{i\in\{1,\dots,j\}}\vvvert e_{i}\vvvert\cdot\max_{i\in\{1,\dots,j\}}\vvvert a_{i}\vvvert

So FF extends to a homomorphism of Banach 𝒜\mathcal{A}-modules

ℱ:⨁i∈{1,…,j}𝒜→ℬ,1i↦ei\mathcal{F}:\bigoplus_{i\in\{1,\dots,j\}}\mathcal{A}\rightarrow\mathcal{B},1_{i}\mapsto e_{i}

Let ℬ−\mathcal{B}^{-} be the image of ℱ\mathcal{F}, it is a Banach finite 𝒜\mathcal{A}-module with the quotient norm ∥⋅∥ℱ\lVert\mathord{\cdot}\rVert_{\mathcal{F}} induced by ℱ\mathcal{F}. As ℬ−\mathcal{B}^{-} is Banach finite over 𝒜\mathcal{A}, it is an affinoid algebra with an affinoid algebra spectral norm ⦀⋅⦀−\vvvert\mathord{\cdot}\vvvert^{-}, which is equivalent to ∥⋅∥ℱ\lVert\mathord{\cdot}\rVert_{\mathcal{F}}. Now on ℬ−\mathcal{B}^{-}, ⦀⋅⦀\vvvert\mathord{\cdot}\vvvert is bounded with respect to ⦀⋅⦀−\vvvert\mathord{\cdot}\vvvert^{-} by the continuity of ℱ\mathcal{F}. To show the reverse, note that ℬ−\mathcal{B}^{-} is dense in ℬ\mathcal{B}, so by Theorem 2.30 one has for any b∈ℬ−b\in\mathcal{B}^{-}

⦀b⦀−=maxz∈𝔐⁡(ℬ−)|b(z)|=maxz∈𝔐⁡(ℬ)|b(z)|=⦀b⦀sp≤⦀b⦀\vvvert b\vvvert^{-}=\max_{z\in\mathfrak{M}(\mathcal{B}^{-})}\lvert b(z)\rvert=\max_{z\in\mathfrak{M}(\mathcal{B})}\lvert b(z)\rvert=\vvvert b\vvvert_{\mathrm{sp}}\leq\vvvert b\vvvert

Therefore ⦀⋅⦀\vvvert\mathord{\cdot}\vvvert and ⦀⋅⦀−\vvvert\mathord{\cdot}\vvvert^{-} are equivalent norms on ℬ−\mathcal{B}^{-}, so ℬ−\mathcal{B}^{-} is closed in ℬ\mathcal{B}, hence coincides with it. ∎

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