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3.3. Foliation of ℝ d \ Q { 0 } λ ​ ( ϵ ) [03DV]

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3.3. Foliation of ℝd\Q{0}λ​(ϵ)\mathbb{R}^{d}\backslash Q^{\lambda}_{\{0\}}(\epsilon)

We will exhibit a vector field on ℝd\Q{0}λ​(ϵ)\mathbb{R}^{d}\backslash Q^{\lambda}_{\{0\}}(\epsilon) with values in ∂Δλ∨⊂ℝd\partial\Delta^{\vee}_{\lambda}\subset\mathbb{R}^{d}. Its integral curves yield the desired foliation ℱ\mathcal{F}. Recall from Lemma 2.3 that there is a subdivision of ∂Δλ∨\partial\Delta^{\vee}_{\lambda} which is combinatorially isomorphic to bsd⁡(S)×T\operatorname{bsd}(S)\times T, restricted to |Σ||\Sigma|. In this context, the projection p2p_{2} can be thought of as defined ∂Δλ∨→∂Δ∨\partial\Delta^{\vee}_{\lambda}\rightarrow{\partial\Delta^{\vee}}, and can be interpreted as a vector field on ∂Δλ∨\partial\Delta^{\vee}_{\lambda}. We will deform p2p_{2}, and extend the deformed vector field to ℝd\Q{0}λ​(ϵ)\mathbb{R}^{d}\backslash Q^{\lambda}_{\{0\}}(\epsilon).

For the deformation part, we use that the faces of bsd⁡(T,T)\operatorname{bsd}(T,T) are parameterized by pairs (τCLOSE,(\tau, 𝔗\mathfrak{T} OPEN=τ0≺…≺τr)∈T×bsd⁡(T)=\tau_{0}\prec\ldots\prec\tau_{r})\in T\times\operatorname{bsd}(T) with τ⪯τ0\tau\preceq\tau_{0} (cf. § 2.2).

Definition.

In the δ\delta-realization of bsd⁡(T,T)\operatorname{bsd}(T,T), the face of bsd⁡(T,T)\operatorname{bsd}(T,T) which corresponds to (τCLOSE,(\tau,𝔗\mathfrak{T})) is the Minkowski sum δ​τ+(1−δ)\delta\tau+(1-\delta)𝔗\mathfrak{T}.

The δ\delta-realization of bsd⁡(T,T)\operatorname{bsd}(T,T) yields a cellular map 𝔡δ:bsd⁡(T,T)→T\mathfrak{d}^{\delta}\colon\operatorname{bsd}(T,T)\rightarrow T, which maps (τCLOSE,(\tau, 𝔗\mathfrak{T})) to τ\tau. (I.e., the small copy of τ\tau in itself is stretched to full size, and the space between the small copies is collapsed into the smallest face.

Lemma 3.4.

If τ1≺τ2\tau_{1}\prec\tau_{2} are simplices of TT, then 𝔡δ\mathfrak{d}^{\delta} is invariant with respect to τ^1−τ^2\widehat{\tau}_{1}-\widehat{\tau}_{2} on the region ⋃θ∈[0,1−δ]θ​τ2^+(1−θ)​τ1\bigcup_{\theta\in[0,1-\delta]}\theta\widehat{\tau_{2}}+(1-\theta)\tau_{1}. In particular, 𝔡δ\mathfrak{d}^{\delta} is constant equal to ww on the whole star of w∈vert⁡(T)w\in\operatorname{vert}(T) in bsd⁡(T,T)\operatorname{bsd}(T,T).

^ τ 2 ^ τ 1

Figure 11: The map 𝔡δ\mathfrak{d}^{\delta} is (τ^1−τ^2\widehat{\tau}_{1}-\widehat{\tau}_{2})-invariant in the shaded region.

Lemma 3.5.

Let KK be a subcomplex of bsd⁡(T)\operatorname{bsd}(T), and let NN be a neighborhood of KK. Then there is a δ\delta-realization of bsd⁡(T,T)\operatorname{bsd}(T,T) such that for each face 𝔗\mathfrak{T} of KK, the faces of bsd⁡(T,T)\operatorname{bsd}(T,T) which correspond to some (τ𝐶𝐿𝑂𝑆𝐸,(\tau, 𝔗\mathfrak{T})) are contained in NN.

We will apply Lemma 3.5 for K=p2​(∂𝒱)K=p_{2}(\partial\mathcal{V}), and N=p2​(N2​(∂𝒱))N=p_{2}(N_{2}(\partial\mathcal{V})), where N2​(∂𝒱)N_{2}(\partial\mathcal{V}) is a neighborhood of ∂𝒱\partial\mathcal{V} in Σ\Sigma.

Proof.

Choose δ\delta small enough to ensure that 𝔗\mathfrak{T} +δ⁡(τ0−τ^0)⊂N+\ \delta(\tau_{0}-\widehat{\tau}_{0})\subset N for every simplex 𝔗\mathfrak{T} =(τ0≺…≺τr)∈K=(\tau_{0}\prec\ldots\prec\tau_{r})\in K.

T ε ( τ 0 - ^ τ 0 ) {

Figure 12: Choice of δ\delta in the proof of Lemma 3.5.

Then the maximal cell which corresponds to (τ0CLOSE,(\tau_{0}, 𝔗\mathfrak{T})) is given by

δ​τ0+(1−δ)​𝔗⊆𝔗+δ⁡(τ0−τ^0)⊂N.\delta\tau_{0}+(1-\delta)\text{\tiny$\mathfrak{T}$}\subseteq\text{\tiny$\mathfrak{T}$}+\delta(\tau_{0}-\widehat{\tau}_{0})\subset N.

∎

Now we are ready to define the vector field 𝔛δ\mathfrak{X}^{\delta} on ∂Δλ∨\partial\Delta^{\vee}_{\lambda} as the composition 𝔡δ​p2:∂Δλ∨→∂Δ∨\mathfrak{d}^{\delta}p_{2}\colon\partial\Delta^{\vee}_{\lambda}\rightarrow{\partial\Delta^{\vee}}. In order to extend 𝔛δ\mathfrak{X}^{\delta} to both sides of ∂Δλ∨\partial\Delta^{\vee}_{\lambda}, we present a polyhedral subdivision of a neighborhood of ∂Δλ∨\partial\Delta^{\vee}_{\lambda} whose trace on ∂Δλ∨\partial\Delta^{\vee}_{\lambda} realizes the restriction of bsd⁡(S)×T\operatorname{bsd}(S)\times T to |Σ||\Sigma|.

Remark.

In § 2.2, we were merely interested in the sphericity of |Σ||\Sigma|. We left open where to place the small copies of faces, and how small we wanted these copies to be. In the following we fix a realization of this subdivision which we will keep through the remainder of the article. In particular, ϵ\epsilon is a fixed constant.

Denote by λϵ∈ℝΔ∩(ℤd)∗\lambda^{\epsilon}\in\mathbb{R}^{\Delta\cap(\mathbb{Z}^{d})^{*}} the vector given by λϵ​(0)=λ⁡(0)\lambda^{\epsilon}(0)=\lambda(0), and λϵ​(v)=λ⁡(v)+ϵ\lambda^{\epsilon}(v)=\lambda(v)+\epsilon for v∈vert⁡(S)v\in\operatorname{vert}(S). Suppose that ϵ>0\epsilon>0 is small enough to ensure that λ\lambda and λϵ\lambda^{\epsilon} induce the same triangulation. Then Δλϵ∨⊂Δλ∨\Delta^{\vee}_{\lambda^{\epsilon}}\subset\Delta^{\vee}_{\lambda} are combinatorially equivalent. For a simplex 𝔖\mathfrak{S} ∈bsd⁡(S)\in\operatorname{bsd}(S), denote 𝔖\mathfrak{S}ϵ the corresponding simplex of bsd⁡(Δλϵ∨)\operatorname{bsd}(\Delta^{\vee}_{\lambda^{\epsilon}}). (I.e., 𝔖\mathfrak{S} ⊂(ℝd)∗\subset(\mathbb{R}^{d})^{*}, while 𝔖\mathfrak{S}ϵ⊂ℝd{}_{\epsilon}\subset\mathbb{R}^{d}.) Given a simplex τ∈T\tau\in T with ⟨\langle𝔖\mathfrak{S},τ⟩=1,\tau\rangle=1, we can form the Minkowski sum 𝔖\mathfrak{S}ϵ+ℝ≥ϵ/2τ{}_{\epsilon}+\mathbb{R}_{\geq\epsilon/2}\tau. These fit together to form a complex of (unbounded) polyhedra which subdivides ℝd\mathbb{R}^{d} outside Δλϵ/2∨\Delta^{\vee}_{\lambda^{\epsilon/2}}. (It actually refines the subdivision into Qσλϵ/2Q^{\lambda^{\epsilon/2}}_{\sigma}’s provided by the non-Archimedean amoeba for λϵ/2\lambda^{\epsilon/2}.)

Δ ∨ λ ( η ) ∂ Δ ∨ λ

Figure 13: The polyhedral subdivision of ℝd\mathbb{R}^{d} outside Δλϵ/2∨\Delta^{\vee}_{\lambda^{\epsilon}/2}.

Definition.

For 0<δ<1/20<\delta<1/2, the vector field 𝔛δ:ℝd\Δλϵ/2∨→∂Δ∨⊂ℝd\mathfrak{X}^{\delta}\colon\mathbb{R}^{d}\backslash\Delta^{\vee}_{\lambda^{\epsilon/2}}\rightarrow{\partial\Delta^{\vee}}\subset\mathbb{R}^{d} is the unique vector field which agrees with 𝔡δ​p2\mathfrak{d}^{\delta}p_{2} on ∂Δλ∨\partial\Delta^{\vee}_{\lambda}, and is invariant with respect to τ^\widehat{\tau} on the polyhedron 𝔖\mathfrak{S}ϵ+ℝ≥ϵ/2τ{}_{\epsilon}+\mathbb{R}_{\geq\epsilon/2}\tau.

We need to argue that this determines a continuous vector field. The problem may arise only when we try to assign a vector to a point n∈n\in 𝔖\mathfrak{S}ϵ+ℝ≥ϵ/2τ{}_{\epsilon}+\mathbb{R}_{\geq\epsilon/2}\tau such that there are two points n1,n2n_{1},n_{2} which already have a vector assigned to them, so that both n−n1n-n_{1} and n−n2n-n_{2} are a multiple of τ^\widehat{\tau}. Then n1∈n_{1}\in 𝔖\mathfrak{S}+ϵ[ϵ/2,ϵ]τ1{}_{\epsilon}+[\epsilon/2,\epsilon]\tau_{1} for some face τ1≺τ\tau_{1}\prec\tau, and 𝔛δ​(n1)\mathfrak{X}^{\delta}(n_{1}) is defined as 𝔛δ​(n1′)\mathfrak{X}^{\delta}(n_{1}^{\prime}), where n1′∈∂Δλ∨n_{1}^{\prime}\in\partial\Delta^{\vee}_{\lambda}, and n1−n1′n_{1}-n_{1}^{\prime} is a multiple of τ^1\widehat{\tau}_{1}. Furthermore, n2∈∂Δλ∨n_{2}\in\partial\Delta^{\vee}_{\lambda}, and n2−n1′n_{2}-n_{1}^{\prime} is a multiple of τ^−τ^1\widehat{\tau}-\widehat{\tau}_{1}. Here we use the assumption that δ<1/2\delta<1/2 to conclude that 𝔛δ​(n2)=𝔡δ​p2​(n2)=𝔡δ​p2​(n1′)=𝔛δ​(n1′)\mathfrak{X}^{\delta}(n_{2})=\mathfrak{d}^{\delta}p_{2}(n_{2})=\mathfrak{d}^{\delta}p_{2}(n_{1}^{\prime})=\mathfrak{X}^{\delta}(n_{1}^{\prime}).

n 1 n n 2 ϵ S ⁢ ϵ 2 ^ τ ⁢ ϵ 2 ^ τ 1

Figure 14: 𝔛δ​(n)\mathfrak{X}^{\delta}(n) is doubly defined: via 𝔛δ​(n1)=𝔛δ​(n1′)\mathfrak{X}^{\delta}(n_{1})=\mathfrak{X}^{\delta}(n_{1}^{\prime}), and via 𝔛δ​(n2)\mathfrak{X}^{\delta}(n_{2}).

The integral curves of 𝔛δ\mathfrak{X}^{\delta} foliate ℝd\Δλϵ/2∨\mathbb{R}^{d}\backslash\Delta^{\vee}_{\lambda^{\epsilon/2}}. The following lemma summarizes the main properties of 𝔛δ\mathfrak{X}^{\delta} and the foliation ℱ\mathcal{F}.

Lemma 3.6.

Given a neighborhood N2​(∂𝒱)N_{2}(\partial\mathcal{V}) of ∂𝒱⊂∂Δλ∨≅Σ\partial\mathcal{V}\subset\partial\Delta^{\vee}_{\lambda}\cong\Sigma, there is a δ>0\delta>0 such that

  1. (1)

    If n∈Qvλϵn\in Q^{\lambda^{\epsilon}}_{v}, then ⟨v,𝔛δ​(n)⟩=1\langle v,\mathfrak{X}^{\delta}(n)\rangle=1.

  2. (2)

    If n∈Vw\N2​(∂𝒱)n\in V_{w}\backslash N_{2}(\partial\mathcal{V}), the flow line ℱn\mathcal{F}_{n} through nn is a straight line parallel to ww outside Δλδ∨\Delta^{\vee}_{\lambda^{\delta}}.

[Uncaptioned image]

Figure 15: The vector field 𝔛δ\mathfrak{X}^{\delta} for a 22-dimensional example.

Proof.

Choose 0<δ<1/20<\delta<1/2 so that the 2​δ2\delta-realization of bsd⁡(T,T)\operatorname{bsd}(T,T) satisfies the conclusion of Lemma 3.5 for K=∂𝒱K=\partial\mathcal{V} and N=p2​(N2​(∂𝒱))N=p_{2}(N_{2}(\partial\mathcal{V})).

By construction of 𝔛δ\mathfrak{X}^{\delta}, the set of values on one of the polyhedra 𝔖\mathfrak{S}ϵ+ℝ≥ϵ/2τ{}_{\epsilon}+\mathbb{R}_{\geq\epsilon/2}\tau is contained in the set of values on its boundary which is contained in τ\tau. Statement (1) follows from ⟨\langle𝔖\mathfrak{S},τ⟩=1,\tau\rangle=1.

For (2), let n∈Vw\N2​(∂𝒱)n\in V_{w}\backslash N_{2}(\partial\mathcal{V}). Then p2​(n)p_{2}(n) belongs to a cell ((𝔗\mathfrak{T},w),w) of the 2​δ2\delta-realization of bsd⁡(T,T)\operatorname{bsd}(T,T), so that 𝔛δ​(n)=w\mathfrak{X}^{\delta}(n)=w. Also, say, n∈U¯vn\in\overline{U}_{v}. If we parameterize ℱn​(t)\mathcal{F}_{n}(t) such that ℱn​(0)=n\mathcal{F}_{n}(0)=n (and ℱ˙n​(t)=𝔛⁡(ℱn​(t))\dot{\mathcal{F}}_{n}(t)=\mathfrak{X}(\mathcal{F}_{n}(t))), then, by (1), ⟨v,ℱn​(t)⟩=λ⁡(v)+t\langle v,\mathcal{F}_{n}(t)\rangle=\lambda(v)+t. So ℱn​(t)−t​τ^\mathcal{F}_{n}(t)-t\widehat{\tau} stays in the hyperplane ⟨v,⋅⟩=1\langle v,\cdot\rangle=1, where τ=carrierT⁡(CLOSE\tau=\operatorname{carrier}_{T}(𝔗\mathfrak{T})).

For t>0t>0, ℱn​(t)=n+t​w\mathcal{F}_{n}(t)=n+tw. For −δ<t<0-\delta<t<0, let ℓ∈(ℝd)∗\ell\in(\mathbb{R}^{d})^{*} be a linear functional which takes the values 00 on ww, and 11 on the opposite side of 𝔗\mathfrak{T}. Then ℓ⁡(p2​(n))<1−2​δ\ell(p_{2}(n))<1-2\delta, and dd​t​ℓ​(p2​(ℱn​(t)−t​τ^))=ℓ⁡(w−τ^)=1\frac{d}{dt}\ell(p_{2}(\mathcal{F}_{n}(t)-t\widehat{\tau}))=\ell(w-\widehat{\tau})=1. So in this time range, ℱn​(t)=n+t​w\mathcal{F}_{n}(t)=n+tw as well. For t<−δt<-\delta, ℱn​(t)\mathcal{F}_{n}(t) belongs to Δλδ∨\Delta^{\vee}_{\lambda^{\delta}} by (1). ∎

Remark.

The foliation ℱ\mathcal{F} can be, in fact, continued to the boundary of Δν{\Delta_{\nu}} (not smoothly at the d−2d-2-skeleton of Δν{\Delta_{\nu}}) via the diffeomorphism μ∘Logs−1\mu\circ\mathrm{Log}_{s}^{-1} between ℝd\mathbb{R}^{d} and the interior of Δν{\Delta_{\nu}}. So that it will induce a projection XΔν\Logs−1​(Q{0}λ​(ϵ))→ΣX_{\Delta_{\nu}}\backslash\mathrm{Log}_{s}^{-1}(Q^{\lambda}_{\{0\}}(\epsilon))\to\Sigma. But to construct torus fibrations we will use only a part of this projection where it is clearly well defined. That is why we do not provide a proof for this more general statement here.

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