ScalingStacks

Proof. [03D7]

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Proof.

Here, Δ∨\Delta^{\vee} is a Minkowski summand of Δλ∨\Delta^{\vee}_{\lambda}. Let ψ\psi be a piecewise linear concave function with domains of linearity given by bsd⁡(Δλ∨;Δ∨)\operatorname{bsd}(\Delta^{\vee}_{\lambda};\Delta^{\vee}). Now ν\nu induces another piecewise linear (non-concave) function ν~\tilde{\nu} on Δλ∨\Delta^{\vee}_{\lambda}, which is ν\nu in GG-direction on (F0≺F2≺⋯≺Fr,G)(F_{0}\prec F_{2}\prec\cdots\prec F_{r},G), and constant in FiF_{i}-direction.

- 3 - 1 - 3 - 3 - 3 - 1 - 1 - 1 - 1 - 1 - 3 - 3 - 1 - 1 - 3 - 3 - 1 - 1

Figure 7: The function ν~\tilde{\nu} on conv⁡[−2 1 1 2 2 0 3−3 2−2−1−1−1−1−1]≺Δλ∨\operatorname{conv}\left[\begin{smallmatrix}-2&\ 1&\ 1&\ 2&\ 2\\ \ 0&\ 3&-3&\ 2&-2\\ -1&-1&-1&-1&-1\end{smallmatrix}\right]\prec\Delta^{\vee}_{\lambda}.

The function ψ\psi is strictly concave wherever ν~\tilde{\nu} is non-concave, so that for large NN, the function N​ψ+ν~N\psi+\tilde{\nu} will be concave. Its domains of linearity are products of simplices that correspond to simplices of bsd⁡(Δλ∨)≅bsd⁡(S)\operatorname{bsd}(\Delta^{\vee}_{\lambda})\cong\operatorname{bsd}(S) times simplices of TT. ∎

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