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Proof: To prove (a), we may assume that is a very affine scheme. A basis of is formed by subsets of the form with all and real numbers . Using the ultrametric triangle inequality, it is easy to see that we may choose the basis in such a way that for all . Note that is contained in the analytification of the very affine open subset of . It is obvious that is a tropical chart proving (a).
To prove (b), let us consider the moment map
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Since is separated, it is easy to see that is a closed embedding and hence is very affine. We conclude that is a very affine open subset of . By definition of a tropical chart, (resp. ) is an open subset of (resp. ). Note that
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is an open subset of . An easy diagram chase yields . Since refines the moment map , we deduce that is a tropical chart. This proves (b).
Finally, we prove (c). Let be the canonical affine homomorphism from 4.12. Then we have on .
Since is a tropical chart, is an open subset of and .
Using , we get for the open subset of . We conclude that is a tropical chart proving (c).