ScalingStacks

Proof. [026Q]

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Proof.

First we assume that |.||\raisebox{1.72218pt}{.}| is discrete. We take a positive integer aa such that e−ϵa/2≤|ϖ|e^{-\epsilon a/2}\leq|\varpi|. We also choose α∈k×\alpha\in k^{\times} such that

|α−1|=min⁡{|γ|∣γ∈k× and ‖l⊗a‖Y,ha≤|γ|}.|\alpha^{-1}|=\min\{|\gamma|\mid\text{$\gamma\in k^{\times}$ and $\|l^{\otimes a}\|_{Y,h^{a}}\leq|\gamma|$}\}.

Then, as ‖l⊗a‖Y,ha≤|α−1|≤|ϖ|−1​‖l⊗a‖Y,ha\|l^{\otimes a}\|_{Y,h^{a}}\leq|\alpha^{-1}|\leq|\varpi|^{-1}\|l^{\otimes a}\|_{Y,h^{a}}, we have

e−aϵ/2≤|ϖ|≤∥αl⊗a∥Y,ha≤1.e^{-a\epsilon/2}\leq|\varpi|\leq\|\alpha l^{\otimes a}\|_{Y,h^{a}}\leq 1.

Next we assume that |.||\raisebox{1.72218pt}{.}| is not discrete. In this case, |k×||k^{\times}| is dense in ℝ>0\mathbb{R}_{>0} by Lemma 1.15, so that we can choose β∈k×\beta\in k^{\times} such that

e−ϵ/2≤∥l∥Y,h/|β|≤1.e^{-\epsilon/2}\leq\|l\|_{Y,h}/|\beta|\leq 1.

Thus if we set α=β−1\alpha=\beta^{-1} and a=1a=1, we have the assertion. ∎

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