ScalingStacks

Proof. [025U]

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Proof.

Let ‖.‖Wk′′\|\raisebox{1.72218pt}{.}\|^{\prime}_{W_{k^{\prime}}} be the quotient norm of ‖.‖V,k′\|\raisebox{1.72218pt}{.}\|_{V,k^{\prime}} with respect to the surjection fk′:Vk′→Wk′f_{k^{\prime}}:V_{k^{\prime}}\to W_{k^{\prime}}. Let ee be an non-zero element of WW. As ‖e‖W,k′=‖e‖W\|e\|_{W,k^{\prime}}=\|e\|_{W}, it is sufficient to show that ‖e‖Wk′′=‖e‖W\|e\|^{\prime}_{W_{k^{\prime}}}=\|e\|_{W}. Note that

{v∈V∣f⁡(v)=e}⊆{v′∈Vk′∣fk′​(v′)=e},\{v\in V\mid f(v)=e\}\subseteq\{v^{\prime}\in V_{k^{\prime}}\mid f_{k^{\prime}}(v^{\prime})=e\},

so that we have ‖e‖W≥‖e‖Wk′′\|e\|_{W}\geq\|e\|^{\prime}_{W_{k^{\prime}}}. Let us consider an inequality ‖e‖W≤‖e‖Wk′′\|e\|_{W}\leq\|e\|^{\prime}_{W_{k^{\prime}}}. For ϵ>0\epsilon>0, let (e1,…,er)(e_{1},\ldots,e_{r}) be an e−ϵe^{-\epsilon}-orthogonal basis of VV such that (e2,…,er)(e_{2},\ldots,e_{r}) forms a basis of Ker⁡(f)\operatorname{Ker}(f). Clearly we may assume that f⁡(e1)=ef(e_{1})=e. Then

‖e‖Wk′′\displaystyle\|e\|^{\prime}_{W_{k^{\prime}}} =inf{∥e1+a2′e2+⋯+ar′er∥V,k′∣a2′,…,ar′∈k′}\displaystyle=\inf\{\|e_{1}+a^{\prime}_{2}e_{2}+\cdots+a^{\prime}_{r}e_{r}\|_{V,k^{\prime}}\mid a^{\prime}_{2},\ldots,a^{\prime}_{r}\in k^{\prime}\}
≥inf{e−ϵmax{∥e1∥,|a2′|′∥e2∥V,…,|ar′|′∥er∥V}∣a2′,…,ar′∈k′}\displaystyle\geq\inf\{e^{-\epsilon}\max\{\|e_{1}\|,|a^{\prime}_{2}|^{\prime}\|e_{2}\|_{V},\ldots,|a^{\prime}_{r}|^{\prime}\|e_{r}\|_{V}\}\mid a^{\prime}_{2},\ldots,a^{\prime}_{r}\in k^{\prime}\}
≥e−ϵ​‖e1‖≥e−ϵ​‖e‖W.\displaystyle\geq e^{-\epsilon}\|e_{1}\|\geq e^{-\epsilon}\|e\|_{W}.

Therefore, we have ‖e‖Wk′′≥‖e‖W\|e\|^{\prime}_{W_{k^{\prime}}}\geq\|e\|_{W} by taking ϵ→0\epsilon\to 0. ∎

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