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Proof.
Pick s , t > 0 s,t>0 . Since (6.1 ) holds for bounded
ω \omega -psh functions, we see using (3.1 ) that
− ∞ < E ( φ + ψ 2 ) ≤ E ( φ ⟨ t ⟩ + ψ ⟨ s ⟩ 2 ) ≤ 2 − ( n + 1 ) n + 1 ∫ ψ ⟨ s ⟩ MA ( φ ⟨ t ⟩ ) . -\infty<E\left(\frac{\varphi+\psi}{2}\right)\leq E\left(\frac{\varphi^{\langle t\rangle}+\psi^{\langle s\rangle}}{2}\right)\leq\frac{2^{-(n+1)}}{n+1}\int\psi^{\langle s\rangle}\MA(\varphi^{\langle t\rangle}).
Since ψ ⟨ s ⟩ \psi^{\langle s\rangle} decreases to ψ \psi at any point of X X , the right hand side converges to
2 − ( n + 1 ) n + 1 ∫ ψ MA ( φ ⟨ t ⟩ ) ≤ 2 − ( n + 1 ) n + 1 ∫ { φ > − t } ψ MA ( φ ⟨ t ⟩ ) = 2 − ( n + 1 ) n + 1 ∫ { φ > − t } ψ MA ( φ ) \frac{2^{-(n+1)}}{n+1}\int\psi\MA(\varphi^{\langle t\rangle})\leq\frac{2^{-(n+1)}}{n+1}\int_{\{\varphi>-t\}}\psi\MA(\varphi^{\langle t\rangle})=\frac{2^{-(n+1)}}{n+1}\int_{\{\varphi>-t\}}\psi\MA(\varphi)
by monotone convergence. We obtain the desired
estimate by letting t → ∞ t\to\infty .
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