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2.8. Radon measures and convergence results [019T]

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2.8. Radon measures and convergence results

We shall make frequent use of basic integration and measure theory. Let XX be a compact (Hausdorff) space. A Radon measure on XX is a positive linear functional μ:C0​(X)→𝐑\mu:C^{0}(X)\to\mathbf{R}. With this definition, it follows from the Riesz representation theorem that Radon measures are in 1-1 correspondence with regular Borel measures on XX; see [Fol99, §7.1–2].

Since we shall be dealing with (possibly uncountable) nets rather than sequences, one has to be careful using results from integration theory. For example, the monotone convergence theorem is of course not true for general nets. However, as the next results show, integration of semicontinuous functions against Radon measures is often well behaved.

Lemma 2.23.

[Fol99, Proposition 7.12]. If μ\mu is a positive Radon measure on XX and (fj)j(f_{j})_{j} a decreasing net of usc functions on XX, converging pointwise to a (usc) function ff, then limj∫fj​μ=∫f​μ\lim_{j}\int f_{j}\mu=\int f\mu.

In particular, one has

Lemma 2.24.

[Fol99, Corollary 7.13]. If μ\mu is a positive Radon measure on XX and ff is a usc function on XX, then

∫fμ=inf{∫gμ∣f≤g,g∈C0(X)}\int f\mu=\inf\left\{\int g\mu\mid f\leq g,\,g\in C^{0}(X)\right\}
Corollary 2.25.

Let (fj)j(f_{j})_{j} a decreasing net of usc functions on XX converging pointwise to a (usc) function ff, and (μj)j(\mu_{j})_{j} a net of positive Radon measures on XX converging weakly to a positive Radon measure μ\mu. Then

lim supj∫fj​μj≤∫f​μ.\limsup_{j}\int f_{j}\mu_{j}\leq\int f\mu.
Proof.

Upon replacing μj\mu_{j} with (∫μj)−1​μj(\int\mu_{j})^{-1}\mu_{j} we may assume that the μj\mu_{j}’s are probability measures. Fix any ε>0\varepsilon>0. By Lemma 2.24 there exists a continuous function g≥fg\geq f on XX such that ∫g​μ<∫f​μ+ε\int g\mu<\int f\mu+\varepsilon. By Dini’s lemma, we have fj<g+εf_{j}<g+\varepsilon for all j≫1j\gg 1, hence

lim supj∫fj​μj≤lim supj∫g​μj+ε=∫g​μ+ε≤∫f​μ+2​ε.\limsup_{j}\int f_{j}\mu_{j}\leq\limsup_{j}\int g\mu_{j}+\varepsilon=\int g\mu+\varepsilon\leq\int f\mu+2\varepsilon.

since ∫g​μj→∫g​μ\int g\mu_{j}\to\int g\mu by the definition of weak convergence. The result follows. ∎

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