ScalingStacks

Verified tagged author-source HTML · 1904.03696v1 · cited publication edition alignment unverified.

00M0

Proof. By the ℚ\mathbb{Q}-independence assumption and Proposition 5.1, for any two distinct multi-index JJ and J′J^{\prime}, and any two non-zero coefficients fJf_{J} and fJ′f_{J^{\prime}} in kk, we have

∥fJ⋅𝑻J∥|J|​ϕ=|fJ|⋅∏i∈{0,…,d}riji≠|fJ′|⋅∏i∈{0,…,d}riji′=∥fJ′⋅𝑻J′∥|J′|​ϕ.\lVert f_{J}\cdot\boldsymbol{T}^{J}\rVert_{|J|\phi}=\lvert f_{J}\rvert\cdot\prod_{i\in\{0,\dots,d\}}r_{i}^{j_{i}}\neq\lvert f_{J^{\prime}}\rvert\cdot\prod_{i\in\{0,\dots,d\}}r_{i}^{j^{\prime}_{i}}=\lVert f_{J^{\prime}}\cdot\boldsymbol{T}^{J^{\prime}}\rVert_{|J^{\prime}|\phi}.

By Lemma 2.13, the elements {𝑻J}J∈S\{\boldsymbol{T}^{J}\}_{J\in S} form an orthogonal basis for the normed vector space (⨁J∈Sk⋅𝑻J,⦀⋅⦀ϕ)(\bigoplus_{J\in S}k\cdot\boldsymbol{T}^{J},\vvvert\mathord{\cdot}\vvvert_{\phi}). So the equality in the conclusion holds. ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.