Proof. By Corollary 2.64, every point in has a neighbourhood system consisting of affinoid domains. Hence for any , there exists an affinoid domain neighbourhood . By Lemma 4.1, has an open neighbourhood , so we can assume that each is contained in this open set.
One forms a covering by open sets
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Since the left hand side is a compact set by Proposition 2.21, there exist finitely many points such that form a covering of . Let be the union of affinoid domains , then it is a special domain, and satisfies the desired inclusion conditions.
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