ScalingStacks

Verified tagged author-source HTML · 1904.03696v1 · cited publication edition alignment unverified.

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Proof. For any M≤m≤2​M−1M\leq m\leq 2M-1, we have t1⊗m∈Vm​(LX|Y)t_{1}^{\otimes m}\in V_{m}(L_{X|Y}). By Corollary 3.27, for any ϵ>0\epsilon>0, there exists Nm∈ℕN_{m}\in\mathbb{N} such that for l≥Nml\geq N_{m},

⦀t1⊗m​l⦀ϕ,X|Y1l/⦀t1⊗m⦀ϕ|Y≤ϵ.\vvvert t_{1}^{\otimes ml}\vvvert_{\phi,X|Y}^{\frac{1}{l}}/\vvvert t_{1}^{\otimes m}\vvvert_{\phi|_{Y}}\leq\epsilon.

It is easy to see that there exists nY∈ℕn_{Y}\in\mathbb{N} such that the set of integers

{ml:l≥Nm,M≤m≤2M−1}\{ml:l\geq N_{m},M\leq m\leq 2M-1\}

contains a subset of form ℕ−{0,…,nY−1}\mathbb{N}-\{0,\dots,n_{Y}-1\}: the case M=1M=1 is clear; if M≥2M\geq 2, the fact that MM and M+1M+1 are coprime guarantees the existence of nYn_{Y}. Note that ⦀⋅⦀ϕ|Y\vvvert\mathord{\cdot}\vvvert_{\phi|_{Y}} is power-multiplicative, so for any n≥nYn\geq n_{Y}, there exists sn∈Vn​(L)s_{n}\in V_{n}(L) with sn|Y=t1⊗ns_{n}|_{Y}=t_{1}^{\otimes n} such that

∥sn∥n​ϕ≤en​ϵ⋅∥t1⊗n∥n​ϕ|Y=en​ϵ⋅(∥t1∥ϕ|Y)n.\lVert s_{n}\rVert_{n\phi}\leq\mathrm{e}^{n\epsilon}\cdot\lVert t_{1}^{\otimes n}\rVert_{n\phi|_{Y}}=\mathrm{e}^{n\epsilon}\cdot(\lVert t_{1}\rVert_{\phi|_{Y}})^{n}.

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