ScalingStacks

Lemma 9.3 . [03JY]

Original official author HTML, exact retained edition. Historical TeX conversion verdicts remain unchanged. Cited-edition alignment and mathematical self-containment are not assessed.

Complete original source context Β· Original author HTML

Lemma 9.3.

Let β„±:𝔄→𝔅\mathscr{F}:\mathfrak{A}\to\mathfrak{B} be a C1C^{1}-map between two Banach spaces such that ℱ⁑(x)βˆ’β„±β‘(0)=ℒ⁑(x)+𝒩⁑(x)\mathscr{F}(x)-\mathscr{F}(0)=\mathscr{L}(x)+\mathscr{N}(x), where the operator β„’:𝔄→𝔅\mathscr{L}:\mathfrak{A}\to\mathfrak{B} is linear and 𝒩⁑(0)=0\mathscr{N}(0)=0. Assume that

  1. (1)

    β„’\mathscr{L} is an isomorphism with β€–β„’βˆ’1‖≀C1\|\mathscr{L}^{-1}\|\leq C_{1},

  2. (2)

    there are constants r>0r>0 and C2>0C_{2}>0 with r<13​C1​C2r<\frac{1}{3C_{1}C_{2}} such that

    1. (a)

      ‖𝒩⁑(x)βˆ’π’©β‘(y)‖𝔅≀C2β‹…(β€–x‖𝔄+β€–y‖𝔄)β‹…β€–xβˆ’y‖𝔄\|\mathscr{N}(x)-\mathscr{N}(y)\|_{\mathfrak{B}}\leq C_{2}\cdot(\|x\|_{\mathfrak{A}}+\|y\|_{\mathfrak{A}})\cdot\|x-y\|_{\mathfrak{A}} for all x,y∈Br​(0)βŠ‚π”„x,y\in B_{r}(0)\subset{\mathfrak{A}},

    2. (b)

      ‖ℱ⁑(0)‖𝔅≀r2​C1\|\mathscr{F}(0)\|_{\mathfrak{B}}\leq\frac{r}{2C_{1}},

then there exists a unique solution to ℱ⁑(x)=0\mathscr{F}(x)=0 in 𝔄\mathfrak{A} such that

(9.92) β€–x‖𝔄≀2​C1⋅‖ℱ⁑(0)‖𝔅.\|x\|_{\mathfrak{A}}\leq 2C_{1}\cdot\|\mathscr{F}(0)\|_{\mathfrak{B}}.

Original mathematics by the credited authors. Source-backed reader collection; mathematical self-containment is not assessed.