Proof.
The uniqueness easily follows from the comparison principle as
we explain in proposition 4.3 below.
We are going to prove the existence by a fixed point method.
Fix such that ,
and let us consider the equation
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where the constant
is chosen so that
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Observe that satisfies condition
,
where .
It follows therefore from Theorem 2.1 that there exists a
unique continuous function solution
to and normalized by .
We use here this linear normalization rather than the
non-linear -normalization: they are comparable
thanks to proposition 2.7 in [GZ 1], which shows that
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for all functions and for
some uniform constant .
Since , we infer
| (6) |
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by observing that since , and
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since .
The important fact here is that the energy of is bounded
from above by a constant which is independent of .
We have thus defined an operator
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which associates to the unique solution
to , where
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It follows from proposition 3.2.3 in [GZ 2] that
is convex. So is the subset of functions
such that .
The set is not convex, but it is relatively
compact in and its closed convex hull
is contained in
for some uniform constant
which only depends on the dimension of :
this follows from easy computations (see lemma 7.2 and the proof of
proposition 3.2 in [GZ 2]).
Therefore maps the compact convex set
into itself if is large enough.
We claim that is continuous.
Let be a sequence of functions which converges
in towards .
We need to show that converges in towards .
Since the set
is relatively
compact in (see proposition 2.7 in [GZ 1]), we can assume – relabelling
if necessary – that converges in towards a function .
We show in lemma 4.2 below that converges in towards .
In particular and,
passing to a subsequence if necessary, we can assume that
for almost every point .
Set
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Observe that decreases towards , while
increases towards at almost
every point. The energy of is controlled by that of
since (see lemma 7.2 in [GZ 2]), and
by (5), therefore
and
.
It follows from an inequality of J.-P.Demailly [Dem 1] that
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where .
Observe that , thus
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Since these are two probability measures, there is actually equality
hence : this shows that is continuous.
We can now invoke Schauder fixed point theorem, which yields a fixed
point .
The function is automatically continuous (by Theorem 2.1, since
satisfies , hence
is the solution we were looking for.
∎