ScalingStacks

Proof. [02DX]

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Proof.

Fix ε>0\varepsilon>0 and α>0\alpha>0 to be chosen later. It follows from (2) and propositions 2.5, 3.1 that

‖φ−ψ‖L∞​(X)≤ε+C1​[C​a​pω​(|φ−ψ|>ε)]α/n.||\varphi-\psi||_{L^{\infty}(X)}\leq\varepsilon+C_{1}\left[Cap_{\omega}(|\varphi-\psi|>\varepsilon)\right]^{\alpha/n}.

Applying the refined version of lemma 2.2 which involves the uniform bound on ‖φ‖L∞​(X),‖ψ‖L∞​(X)||\varphi||_{L^{\infty}(X)},||\psi||_{L^{\infty}(X)} (see inequality (3)), we obtain

C​a​pω​(|φ−ψ|>ε)≤C2εn+2/q​∫X|φ−ψ|2/q​(f+g)​ωn.Cap_{\omega}(|\varphi-\psi|>\varepsilon)\leq\frac{C_{2}}{\varepsilon^{n+2/q}}\int_{X}|\varphi-\psi|^{2/q}(f+g)\omega^{n}.

It follows thus from Hölder’s inequality that

C​a​pω​(|φ−ψ|>ε)≤C3​‖f+g‖Lpεn+2/q​[‖φ−ψ‖L2​(ωn)]2/q.Cap_{\omega}(|\varphi-\psi|>\varepsilon)\leq\frac{C_{3}||f+g||_{L^{p}}}{\varepsilon^{n+2/q}}\left[||\varphi-\psi||_{L^{2}(\omega^{n})}\right]^{2/q}.

Choose now ε:=‖φ−ψ‖L2ω\varepsilon:=||\varphi-\psi||_{L^{2}}^{\omega} where 0<γ<2/(2+n​q)0<\gamma<2/(2+nq). Then

C​a​pω​(|φ−ψ|>ε)≤C4​[‖φ−ψ‖L2]2/q−γ⁡(n+2/q).Cap_{\omega}(|\varphi-\psi|>\varepsilon)\leq C_{4}\left[||\varphi-\psi||_{L^{2}}\right]^{2/q-\gamma(n+2/q)}.

We infer

‖φ−ψ‖L∞​(X)≤||φ−ψ||L2γ+C5​‖φ−ψ‖L2γ′, where ​γ′=αn​[2/q−γ⁡(n+2/q)].||\varphi-\psi||_{L^{\infty}(X)}\leq||\varphi-\psi||_{L^{2}}^{\gamma}+C_{5}||\varphi-\psi||_{L^{2}}^{\gamma^{\prime}},\;\text{ where }\gamma^{\prime}=\frac{\alpha}{n}\left[2/q-\gamma(n+2/q)\right].

We finally choose α>0\alpha>0 so large that γ≤γ′\gamma\leq\gamma^{\prime} and adjust the value of the constant CC: this yields the desired estimate. ∎

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