Set . Observe that when ,
, hence it follows from lemma 2.2
that for all , ,
| (3) |
|
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|
using the obvious substitutions , .
Since satisfies , we infer
|
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|
Consider
|
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|
Then satisfies the condition of lemma 2.3 with
.
Assume
.
It follows in this case from Remarks 2.4
that for , where
|
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|
Therefore the sets are empty for
, hence
|
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|
Thus we can take here .
If , then
|
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|
by (2), hence it suffices to take to conclude.
∎