ScalingStacks

Proof. [01YZ]

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Proof.

(of Theorem 1.3) Let (Mn,g,p)(M^{n},g,p) satisfy |RicMn|≤n−1|{\rm Ric}_{M^{n}}|\leq n-1 and Vol⁡(B1​(p))>v>0{\rm Vol}(B_{1}(p))>{\rm v}>0. We will first show that for every q<2q<2 there exists C=C⁡(n,v,q)>0C=C(n,{\rm v},q)>0 such that

⨏B1​(p)rh−2​q≤C.\displaystyle\fint_{B_{1}(p)}r_{h}^{-2q}\leq C\,. (7.3)

Simultaneously, we will show that if MnM^{n} is Einstein, then this can be improved to

⨏B1​(p)rx−2​q≤C,\displaystyle\fint_{B_{1}(p)}r_{x}^{-2q}\leq C\,, (7.4)

where rxr_{x} denotes the regularity scale at xx.

Let q<2q<2 and set η=4−2​q\eta=4-2q. Consider Theorem 7.3 with ϵ=ϵ⁡(n)>0\epsilon=\epsilon(n)>0 chosen from Theorem 6.1 and η\eta as above. Thus, there exists C⁡(n,v,q)C(n,{\rm v},q) such that

Vol(Tr({x∈𝒮ϵ,2​rn−4∩B1(p)}))<Cr4−η.\displaystyle{\rm Vol}(T_{r}(\{x\in\mathcal{S}^{n-4}_{\epsilon,2r}\cap B_{1}(p)\}))<Cr^{4-\eta}\,. (7.5)

Note that by rescaling, we may regard the ϵ\epsilon-regularity theorem (Theorem 6.1) as stating that if xx is (n−3,ϵ,2​r)(n-3,\epsilon,2r)-symmetric then rh>rr_{h}>r, and if MnM^{n} is Einstein then rx>rr_{x}>r. In fact, we have that if xx is (n−3,ϵ,s)(n-3,\epsilon,s)-symmetric for any s≥2​rs\geq 2r, then rh>rr_{h}>r. This is to say that if x∉𝒮ϵ,2​rn−4x\not\in\mathcal{S}^{n-4}_{\epsilon,2r}, then rh>s2>rr_{h}>\frac{s}{2}>r. The contrapositive gives the inclusion

{x∈B1​(p):rh≤r}⊆𝒮ϵ,2​rn−4∩B1​(p).\displaystyle\{x\in B_{1}(p):r_{h}\leq r\}\subseteq\mathcal{S}^{n-4}_{\epsilon,2r}\cap B_{1}(p)\,. (7.6)

which by (7.5) gives us the desired estimate

Vol⁡(Tr​({x∈B1​(p):rh≤r}))<C​r4−η≤C​r2​p.\displaystyle{\rm Vol}(T_{r}(\{x\in B_{1}(p):r_{h}\leq r\}))<Cr^{4-\eta}\leq Cr^{2p}\,. (7.7)

If MnM^{n} is Einstein, then Theorem 6.1 allows us to replace rhr_{h} with rxr_{x}, as claimed.

Now, for q<2q<2, let us prove the LqL^{q} bound on the curvature from Theorem 1.3. For this note that if rh​(x)>rr_{h}(x)>r then by definition there exists harmonic coordinates Φ:Br​(0n)→M\Phi:B_{r}(0^{n})\to M with ϕ⁡(0)=x\phi(0)=x and such that

‖gi​j−ηi​j‖C0​(Br​(0))+r​‖∂kgi​j‖C0​(Br​(0))<10−3,\displaystyle||g_{ij}-\eta_{ij}||_{C^{0}(B_{r}(0))}+r||\partial_{k}g_{ij}||_{C^{0}(B_{r}(0))}<10^{-3}\,, (7.8)

where gi​j=Φ∗​gg_{ij}=\Phi^{*}g is the pullback metric. Since the Ricci curvature satisfies the bound |RicMn|≤n−1|{\rm Ric}_{M^{n}}|\leq n-1, this implies that

|Δx​gi​j|<C⁡(n)​r−2,\displaystyle|\Delta_{x}g_{ij}|<C(n)r^{-2}\,, (7.9)

where Δx\Delta_{x} denotes the Laplacian written in coordinates. In particular, for every α<1\alpha<1 and s<∞s<\infty, we have the scale invariant estimates

r1+α​‖∂kgi​j‖Cα​(B3​r4​(0))≤C⁡(n,α),\displaystyle r^{1+\alpha}||\partial_{k}g_{ij}||_{C^{\alpha}(B_{\frac{3r}{4}}(0))}\leq C(n,\alpha)\,,
r2​‖gi​j‖W2,s​(B3​r4​(0))≤C⁡(n,s).\displaystyle r^{2}||g_{ij}||_{W^{2,s}(B_{\frac{3r}{4}}(0))}\leq C(n,s)\,. (7.10)

In particular, applying this to s=qs=q we get

r2​q​⨏Br/2​(x)|Rm|q≤C⁡(n)​r2​q​⨏B3​r/4​(0)|Φ∗​Rm|q<C⁡(n,q).\displaystyle r^{2q}\fint_{B_{r/2}(x)}|{\rm Rm}|^{q}\leq C(n)r^{2q}\fint_{B_{3r/4}(0)}|\Phi^{*}{\rm Rm}|^{q}<C(n,q)\,. (7.11)

Let η=2−q\eta=2-q be chosen so that q+η2<2q+\frac{\eta}{2}<2. Then we have already shown that

Vol⁡(Tr​({x∈B1​(p):rh≤r}))<C​r2​q+η,\displaystyle{\rm Vol}(T_{r}(\{x\in B_{1}(p):r_{h}\leq r\}))<Cr^{2q+\eta}\,, (7.12)

for C⁡(n,v,q)>0C(n,{\rm v},q)>0. Consider the covering {Brh​(x)​(x)}\{B_{r_{h}(x)}(x)\} of B1​(p)B_{1}(p), and a subcovering {Brj​(xj)}\{B_{r_{j}}(x_{j})\} by mutually disjoint balls, such that

  1. (1)

    B1​(p)⊆⋃Brj​(xj)B_{1}(p)\subseteq\bigcup B_{r_{j}}(x_{j}) with rj=12​rh​(x)r_{j}=\frac{1}{2}r_{h}(x).

  2. (2)

    {Brj/4​(xj)}\{B_{r_{j}/4}(x_{j})\} are disjoint.

By using (7.12), we see for each α∈ℕ\alpha\in\mathds{N} that

∑2−α−1<rj≤2−αVol⁡(Brj​(xj))≤C​rj2​q+η=C​rj2​q​ 2−η​α.\displaystyle\sum_{2^{-\alpha-1}<r_{j}\leq 2^{-\alpha}}{\rm Vol}(B_{r_{j}}(x_{j}))\leq Cr_{j}^{2q+\eta}=C\,r_{j}^{2q}\,2^{-\eta\alpha}\,. (7.13)

Summing over α\alpha this gives

∑rj−2​q​Vol​(Brj​(xj))≤C​∑2−η​α≤C⁡(n,v,q).\displaystyle\sum r_{j}^{-2q}{\rm Vol}(B_{r_{j}}(x_{j}))\leq C\sum 2^{-\eta\alpha}\leq C(n,{\rm v},q)\,. (7.14)

Finally, combining this with (7.11) we get

⨏B1​(p)|Rm|q\displaystyle\fint_{B_{1}(p)}|{\rm Rm}|^{q} ≤C⁡(n,v)​∑∫Brj​(xj)|Rm|q\displaystyle\leq C(n,{\rm v})\sum\int_{B_{r_{j}}(x_{j})}|{\rm Rm}|^{q}
≤C⁡(n,v,q)​∑rj−2​q​Vol​(Brj​(xj))≤C⁡(n,v,q),\displaystyle\leq C(n,{\rm v},q)\sum r_{j}^{-2q}{\rm Vol}(B_{r_{j}}(x_{j}))\leq C(n,{\rm v},q)\,, (7.15)

which finishes the proof of Theorem 1.3. ∎

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