ScalingStacks

Proof. [05DK]

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Proof.

If ωE|S¯≠0\omega_{E}|_{\bar{S}}\neq 0, and thus ω0|S≠0\omega_{0}|_{S}\neq 0, then there are two vectors v1,v2∈S¯v_{1},v_{2}\in\bar{S} such that ωE​(v1,v2)>0\omega_{E}(v_{1},v_{2})>0. By perturbing v1v_{1} and v2v_{2} a little bit if necessary, we have that Σ~=𝔮⁡({t1​v1+t2​v2|ti∈ℝ})\tilde{\Sigma}=\mathfrak{q}(\{t_{1}v_{1}+t_{2}v_{2}|t_{i}\in\mathbb{R}\}) is a closed 2-torus in S~\tilde{S}, i.e. a closed 2-parameters subgroup. Thus Σ=πh​(Σ~)\Sigma=\pi_{h}(\tilde{\Sigma}) is a closed oriented surface in SS, which satisfies

∫Σω0≥1λ⁡(n)​∫Σ~πh∗​ω0≥ωE​(v1,v2)λ⁡(n)​‖v1∧v2‖hE​VE>0,\int_{\Sigma}\omega_{0}\geq\frac{1}{\lambda(n)}\int_{\tilde{\Sigma}}\pi_{h}^{*}\omega_{0}\geq\frac{\omega_{E}(v_{1},v_{2})}{\lambda(n)\|v_{1}\wedge v_{2}\|_{h_{E}}}V_{E}>0,

where VEV_{E} denotes the Euclidean area of the intersection of {t1​v1+t2​v2|ti∈ℝ}\{t_{1}v_{1}+t_{2}v_{2}|t_{i}\in\mathbb{R}\} with the fundamental domain of the quotient map 𝔮\mathfrak{q}. From the smooth convergence of (Mk,ω~k,g~k)(M_{k},\tilde{\omega}_{k},\tilde{g}_{k}),

limk⟶∞igk−2​(pk)​∫Fr,k​(Σ)ωk=limk⟶∞∫Fr,k​(Σ)ω~k=limk⟶∞∫ΣFr,k∗​ω~k=∫Σω0,\lim_{k\longrightarrow\infty}i^{-2}_{g_{k}}(p_{k})\int_{F_{r,k}(\Sigma)}\omega_{k}=\lim_{k\longrightarrow\infty}\int_{F_{r,k}(\Sigma)}\tilde{\omega}_{k}=\lim_{k\longrightarrow\infty}\int_{\Sigma}F_{r,k}^{*}\tilde{\omega}_{k}=\int_{\Sigma}\omega_{0},

for r≫1r\gg 1 such that Σ⊂Bg0​(p0,r)\Sigma\subset B_{g_{0}}(p_{0},r). Thus

0<12​igk2​(pk)​∫Σω0≤∫Fr,k​(Σ)ωk≤2​igk2​(pk)​∫Σω0≤2​k−2​∫Σω0<1,0<\frac{1}{2}i^{2}_{g_{k}}(p_{k})\int_{\Sigma}\omega_{0}\leq\int_{F_{r,k}(\Sigma)}\omega_{k}\leq 2i^{2}_{g_{k}}(p_{k})\int_{\Sigma}\omega_{0}\leq 2k^{-2}\int_{\Sigma}\omega_{0}<1,

for k≫1k\gg 1. Since [Fr,k​(Σ)]∈H2​(Mk,ℤ)[F_{r,k}(\Sigma)]\in H_{2}(M_{k},\mathbb{Z}) and [ωk]∈H2​(Mk,ℤ)[\omega_{k}]\in H^{2}(M_{k},\mathbb{Z}), we obtain

∫Fr,k​(Σ)ωk∈ℤ,\int_{F_{r,k}(\Sigma)}\omega_{k}\in\mathbb{Z},

which is a contradiction. Hence ωE|S¯≡0\omega_{E}|_{\bar{S}}\equiv 0 and ω0|S≡0\omega_{0}|_{S}\equiv 0, which implies that SS is a lagrangian submanifold (X,ω0)(X,\omega_{0}) by combining Lemma 3.1.

Since S¯\bar{S} is a lagrangian linear subspace of (ℂn,ωE)(\mathbb{C}^{n},\omega_{E}), there is a θ0∈ℝ\theta_{0}\in\mathbb{R} such that Im​e−1​θ0​ΩE|S¯=0{\rm Im}e^{\sqrt{-1}\theta_{0}}\Omega_{E}|_{\bar{S}}=0. This implies that S¯\bar{S} is a special lagrangian linear subspace of phase θ0\theta_{0} in (ℂn,ωE,ΩE)(\mathbb{C}^{n},\omega_{E},\Omega_{E}). Thus SS is a special lagrangian submanifold of phase θ0\theta_{0} in (X,ω0,Ω0)(X,\omega_{0},\Omega_{0}), i.e.

ω0|S=0,Im​e−1​θ0​Ω0|S=0.\omega_{0}|_{S}=0,\ \ \ {\rm Im}e^{\sqrt{-1}\theta_{0}}\Omega_{0}|_{S}=0.

∎

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