ScalingStacks

Verified tagged author-source HTML · 2007.01384v1 · cited publication edition alignment unverified.

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Corollary 4.6. Given small numbers 0<λ,κ≪10<\lambda,\kappa\ll 1, then for tt small enough depending on λ,κ\lambda,\kappa, there exist appropriately chosen local potentials ϕC​Y,J,t\phi_{CY,J,t} on Log𝒳−1​(Int​(ΔJ))\text{Log}_{\mathcal{X}}^{-1}(\text{Int}(\Delta_{J})), normalized to inf(ϕC​Y,J,t−ϕ0∘Log𝒳)=0\inf(\phi_{CY,J,t}-\phi_{0}\circ\text{Log}_{\mathcal{X}})=0, satisfying

dμt({ϕC​Y,J,t−ϕ0∘Log𝒳≥κ/4})<λ,d\mu_{t}(\{\phi_{CY,J,t}-\phi_{0}\circ\text{Log}_{\mathcal{X}}\geq\kappa/4\})<\lambda,

and ‖ϕC​Y,J,t−ϕ0∘Log𝒳‖L∞≤C\left\lVert\phi_{CY,J,t}-\phi_{0}\circ\text{Log}_{\mathcal{X}}\right\rVert_{L^{\infty}}\leq C independent of λ,κ\lambda,\kappa and small tt.

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Proof. By construction in Lemma 4.1, the local potential ϕJ,t\phi_{J,t} of ωF​S,t\omega_{FS,t} is ϵ\epsilon-close to ϕ0∘Log𝒳\phi_{0}\circ\text{Log}_{\mathcal{X}}, and since ϵ≪κ\epsilon\ll\kappa these two are practically the same. Up to an overall normalisation constant, which is fixed by inf=0\inf=0, we have ϕC​Y,J,t=ϕC​Y,t+ϕJ,t,\phi_{CY,J,t}=\phi_{CY,t}+\phi_{J,t}, so the measure bound follows from the previous result.

The uniform L∞L^{\infty} bound follows from Prop. 4.3 and Lemma 4.1 without any reference to λ,κ\lambda,\kappa. ∎

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